Thanks Man,
Working fine with me.
On Monday, 2 March 2015 03:25:22 UTC+5:30, Leonel Câmara wrote:
>
> Turns out you're right, here's a possible workaround:
>
> def register():
> db.purchase.coupon_code.show_if = (db.purchase.have_coupon ==
> 'Individual')
>
> form=SQLFORM.factory(db.cli
Turns out you're right, here's a possible workaround:
def register():
db.purchase.coupon_code.show_if = (db.purchase.have_coupon ==
'Individual')
form=SQLFORM.factory(db.client,db.address,db.purchase)
form.element(_id='no_table_coupon_code')['_data-show-trigger'] =
'no_table_have_co
Ya why don't you try your self with SQLFORM and SQLFORM.factory with multiple
tables. Than use show_if than you will get it what I want.
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Did you include those fields in the factory?
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Its working fine with SQLFORM() but its not working with SQLFORM.factory()
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db.purchase.coupon_code.show_if = (db.purchase.have_coupon=='Individual')
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You received this message becau
Sorry syntax mistack it was show_if=='Individual'
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I don't usually use show_if but I'm guessing it's because a
db.purchase.have_coupon is not == to True. Which makes sense since it's a
string. You can test in the python interpreter 'abc' == True, the result
will be False.
The correct form would be:
db.purchase.coupon_code.show_if = (db.purch
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