I have not tried it but it will run. Thank very much.
Check that you've got the pywin32 module installed.
http://pypi.python.org/pypi/pywin32/214
~Brian
Still the same error.
And if you change ip = '0.0.0.0' and comment the line 'interfaces' ?
On 20 oct, 08:36, toan75 wrote:
> Yes, i renamed options_std.py to options.py.
>
> import socket
> import os
>
> ip = '192.168.0.1'
> port = 80
> interfaces=[('0.0.0.0',80),('0.0.0.0',443,'ssl_private_key.pem','ssl_certif
> ica
Yes, i renamed options_std.py to options.py.
import socket
import os
ip = '192.168.0.1'
port = 80
interfaces=[('0.0.0.0',80),('0.0.0.0',443,'ssl_private_key.pem','ssl_certificate.pem')]
password = '' # ## means use the previous password
pid_filename = 'httpserver.pid'
log_filename = 'httpserver
Did you create an options.py file, as per the instructions
here: http://web2py.com/book/default/chapter/11#Start-as-Windows-Service?
On Wednesday, October 19, 2011 10:12:19 PM UTC-4, toan75 wrote:
>
>
>
>
> HI ALL,
>
> I can't run web2py as windows server 2003 service.
> Pls help me. Thanks very
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