http://172.18.4.138:8080/BigBrother"+ ");
out.println("");
out.println("");
}
catch (Exception
ables in a "doget" program.
Waiting for your help..
Best,
ilker
Rashmi Rubdi-2 wrote:
>
> On 6/1/07, ibozo <[EMAIL PROTECTED]> wrote:
>>
>> Hello all,
>>I have created a file of servlet pages that publish those pages in
>> Tomcat
>> 6.
Hello all,
I have created a file of servlet pages that publish those pages in Tomcat
6. I have a log in page, programmed by servlet and also another page that
activates the application acording to the given parameters by serching
webserver. I should use the taken variable on the log in page in