Hi!
Run cmd, "cd" to the bin directory of the Tomcat directory structure
and type the following command:
java -jar bootstrap.jar
When you want to stop Tomcat, simply press Ctrl+C...
Or download installer-less binary distribution of the Tomcat and use
provided .cmd files in the same directory...
My notes for Eclipse:
Eclipse is using some piece of code for compiling. I didn't assembly
it, but I think, there is in the J2SE JRE, in the standard Java
library several classes they provide compiling. This means, you DON'T
NEED J2SE SDK or Java 5 JDK.
I'm using this "feature" on windoze machine
Hi,
here is some more informations about JNDI, PostgreSQL, etc:
I wrote, I had the same problem, and here is my solution:
Create in your development environment (Eclipse, NetBeans, Midnight
Commander...) the META-INF/context.xml with the following content:
Add to your WEB-INF/web.xml the
Hi,
I have the following problem. I found this solution:
There is in the server.xml the Resource tag describing your
dataSource. Move this element into the Context element in the same xml
file (at the bottom).
See http://tomcat.apache.org/tomcat-5.5-doc/jndi-resources-howto.html
section `JDBC Da
Deepa,
The java.lang.NoClassDefFoundError: com/deepa/servlet/DownloadFiles
(wrong name: DownloadFiles) error message means that you have class
DownloadFiles in the package directory structure
com.deepa.servlet.DownloadFiles, but you ommit the package directive
in the source code, OR you have corre
test it!
Thank you very much!
PETR
On 1/23/06, Caldarale, Charles R <[EMAIL PROTECTED]> wrote:
> > From: Petr Hadraba [mailto:[EMAIL PROTECTED]
> > Subject: Re: (newb) Tomcat servlet mapping problem
> >
> > How can I ommit the servlet name in the URL?
>
> Your
:8080/path_in_the_servlet_and arguments
I will run under Tomcat only one servlet; and I want to handle all the domain.
To override "DefaultServlet" is, I think, not so good solution, isn't it?
Thank you very much for your tips.
PETR
On 1/23/06, Petr Hadraba <[EMAIL PROTECTED]> wrote:
>
Hi,
sorry for my question, but I'm googling, reading manuals and still no answer...
So. The question si very simple:
How can I ommit the servlet name in the URL?
Ex.: I have http://localhost:8080/ServletTest/path_in_the_servlet_and arguments
and I need http://localhost:8080/path_in_the_servlet