On Thu, 04 Feb 2010 16:06:08 -0200, Vangel V. Ajanovski
wrote:
For example in 100% of cases we have source of the grid as
List, where Employee is an Entity (via Hibernate).
And in 90% the cells we have something like this
${employee.person.firstName}
${employee.person.lastName}
You could, f
On 26.01.2010 20:00, Michael Prescott wrote:
> How do you go about making a computed column in a Grid sortable? The docs
> on Grid are great, but in the example the computed column is non-sortable.
> Can I do it by providing a PropertyConduit through the grid's BeanModel
> model?
>
> Michael
>
>
On Wed, Jan 27, 2010 at 9:14 AM, Norman Franke wrote:
> I ran into a similar problem. IMHO, the Grid component seems frustratingly
> half-finished. No default sort, no easy to modify sorting behaviors, etc.
It could use some TLC, and needs to be better split out into reusable
sub-components, so t
I ran into a similar problem. IMHO, the Grid component seems
frustratingly half-finished. No default sort, no easy to modify
sorting behaviors, etc.
You can't set the sortable property on the property model, since the
data model is completely overwritten in Grid's setupDataModel method.
Y
That is the right approach, a smarter implementation of a property
within the BeanModel that can handle the sorting.
On Tue, Jan 26, 2010 at 11:00 AM, Michael Prescott
wrote:
> How do you go about making a computed column in a Grid sortable? The docs
> on Grid are great, but in the example the c
How do you go about making a computed column in a Grid sortable? The docs
on Grid are great, but in the example the computed column is non-sortable.
Can I do it by providing a PropertyConduit through the grid's BeanModel
model?
Michael
