Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Ralph Castain
Also the sequential mapper may be of help - allows you to specify the node each rank is to be place on, one line/rank. On Mar 1, 2012, at 12:40 PM, Gustavo Correa wrote: > Hi Claudio > > Check 'man mpirun'. > You will find examples of the > '-byslot', '-bynode', '-loadbalance', and rankfile

Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Gustavo Correa
Hi Claudio Check 'man mpirun'. You will find examples of the '-byslot', '-bynode', '-loadbalance', and rankfile options, which allow some control of how ranks are mapped into processors/cores. I hope this helps, Gus Correa On Mar 1, 2012, at 2:34 PM, Claudio Pastorino wrote: > Hi, thanks for

Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Claudio Pastorino
Probably yes, do I have a more systematic way? Thanks Claudio 2012/3/1, Jingcha Joba : > mpirun -np 4 --host node1,node2,node1,node2 ./app > > Is this what you want? > > On Thu, Mar 1, 2012 at 10:57 AM, Claudio Pastorino < > claudio.pastor...@gmail.com> wrote: > >> Dear all, >> I apologize in adv

Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Claudio Pastorino
Hi, thanks for the answer. You are right is not the rank what matters but how do I arrange the physical procs in the cartesian topology. I don't care about the label. So, how do I achieve that? Regards, Claudio 2012/3/1, Ralph Castain : > Is it really the rank that matters, or where the rank i

Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Jingcha Joba
mpirun -np 4 --host node1,node2,node1,node2 ./app Is this what you want? On Thu, Mar 1, 2012 at 10:57 AM, Claudio Pastorino < claudio.pastor...@gmail.com> wrote: > Dear all, > I apologize in advance if this is not the right list to post this. I > am a newcomer and please let me know if I should

Re: [OMPI users] Redefine proc in cartesian topologies

2012-03-01 Thread Ralph Castain
Is it really the rank that matters, or where the rank is located? For example, you could leave the ranks as assigned by the cartesian topology, but then map them so that ranks 0 and 2 share a node, 1 and 3 share a node, etc. Is that what you are trying to achieve? On Mar 1, 2012, at 11:57 AM,