On Sat, Jun 19, 2010 at 7:05 PM, Patrick O'Callaghan
wrote:
> A script I'm writing needs to work out the target of a symbolic link,
> i.e. given:
>
> $ touch foo
> $ ln -s foo bar
>
> the function should print bar when given foo as a parameter. The manual
> says "ls -L" should do this, but it does
On Sat, 2010-06-19 at 22:34 -0400, Sam Varshavchik wrote:
> > Have I misunderstood what "ls -L" does?
>
> Yes, you did. The description of the -L option reads:
>
>-L, --dereference
> when showing file information for a symbolic link, show
> informa-
> tion for
On 19Jun2010 21:35, Patrick O'Callaghan wrote:
| A script I'm writing needs to work out the target of a symbolic link,
| i.e. given:
|
| $ touch foo
| $ ln -s foo bar
|
| the function should print bar when given foo as a parameter.
>From your examples below, you mean "print foo when given bar a
On 06/19/2010 07:05 PM, Patrick O'Callaghan was caught red-handed while
writing::
> A script I'm writing needs to work out the target of a symbolic link,
> i.e. given:
>
> $ touch foo
> $ ln -s foo bar
>
> the function should print bar when given foo as a parameter. The manual
> says "ls -L" sho
Patrick O'Callaghan writes:
A script I'm writing needs to work out the target of a symbolic link,
i.e. given:
$ touch foo
$ ln -s foo bar
the function should print bar when given foo as a parameter. The manual
says "ls -L" should do this, but it doesn't seem to work:
$ touch foo
$ ln -s foo b
On Sun, Jun 20, 2010 at 7:35 AM, Patrick O'Callaghan
wrote:
> A script I'm writing needs to work out the target of a symbolic link,
> i.e. given:
>
> $ touch foo
> $ ln -s foo bar
>
> the function should print bar when given foo as a parameter. The manual
> says "ls -L" should do this, but it does
