>>
>>> >> On Thu, Jul 31, 2014 at 12:27 PM, buntu wrote:
>>> >> > I'm looking to write a select statement to get a distinct count on
>>> >> > userId
>>> >> > grouped by keyword column on a parquet file SchemaRDD equivalent of:
>>
column on a parquet file SchemaRDD equivalent of:
>> >> > SELECT keyword, count(distinct(userId)) from table group by keyword
>> >> >
>> >> > How to write it using the chained select().groupBy() operations?
>> >> >
>> >> > Thanks!
>> >> >
>> >> >
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>> http://apache-spark-user-list.1001560.n3.nabble.com/SchemaRDD-select-expression-tp11069.html
>> >> > Sent from the Apache Spark User List mailing list archive at
>> Nabble.com.
>> >
>> >
>>
>
>
gt;> > userId
> >> > grouped by keyword column on a parquet file SchemaRDD equivalent of:
> >> > SELECT keyword, count(distinct(userId)) from table group by keyword
> >> >
> >> > How to write it using the chained select().groupBy() operations?
>
erId
>> > grouped by keyword column on a parquet file SchemaRDD equivalent of:
>> > SELECT keyword, count(distinct(userId)) from table group by keyword
>> >
>> > How to write it using the chained select().groupBy() operations?
>> >
>> > Thanks!
&
SELECT keyword, count(distinct(userId)) from table group by keyword
> >
> > How to write it using the chained select().groupBy() operations?
> >
> > Thanks!
> >
> >
> >
> > --
> > View this message in context:
> http://apache-spark-user-lis
; --
> View this message in context:
> http://apache-spark-user-list.1001560.n3.nabble.com/SchemaRDD-select-expression-tp11069.html
> Sent from the Apache Spark User List mailing list archive at Nabble.com.
hanks!
--
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