tln)
>
>
> This outputs the following . I think this may be essentially what u r looking
> for
>
> (I have to understand how to NOT print as CompactBuffer)
>
> (2,CompactBuffer(1001,1000,1002,1003, 1004,1001,1006,1007))
> (3,CompactBuffer(1011,1012,1013,1010, 1007,1009,1005,1008))
> (
spark.apache.org"
Sent: Saturday, January 3, 2015 8:15 PM
Subject: Re: Joining by values
call `map(_.toList)` to convert `CompactBuffer` to `List`
Best Regards,Shixiong Zhu
2015-01-04 12:08 GMT+08:00 Sanjay Subramanian
:
hi Take a look at the code here I
wrotehttps://raw.
int as CompactBuffer)
>
> (2,CompactBuffer(1001,1000,1002,1003, 1004,1001,1006,1007))
> (3,CompactBuffer(1011,1012,1013,1010, 1007,1009,1005,1008))
> (1,CompactBuffer(1001,1000,1002,1003, 1011,1012,1013,1010,
> 1004,1001,1006,1007, 1007,1009,1005,1008))
>
>
>
6,1007))
(3,CompactBuffer(1011,1012,1013,1010, 1007,1009,1005,1008))
(1,CompactBuffer(1001,1000,1002,1003, 1011,1012,1013,1010, 1004,1001,1006,1007,
1007,1009,1005,1008))
From: Sanjay Subramanian
To: dcmovva ; "user@spark.apache.org"
Sent: Saturday, January 3, 2015 12:19 PM
Subject: Re:
This is my design. Now let me try and code it in Spark.
rdd1.txt =1~4,5,6,72~4,53~6,7
rdd2.txt
4~1001,1000,1002,10035~1004,1001,1006,10076~1007,1009,1005,10087~1011,1012,1013,1010
TRANSFORM 1===map each value to key (like an inverted
index)4~15~16~17~15~24~26~37~3
TRANSFOR
