uot;string")
).show();
Regards,
Vibhor Gupta
From: mar...@wunderlich.com
Sent: Thursday, November 18, 2021 5:37 PM
To: Vibhor Gupta
Cc: sebastian....@gmail.com ; user
Subject: Re: EXT: Re: Create Dataframe from a single String in Java
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Cc: user
Subject: EXT: Re: Create Dataframe from a single String in Java
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You can call that on sparkSession to
On Thu, 18 Nov 2021, 10:48 , wrote:
PS: The following works, but it seems rather awkward having to use the
SQLContext here.
SQLCon
From: Sebastian Piu
Sent: Thursday, November 18, 2021 4:20 PM
To: mar...@wunderlich.com
Cc: user
Subject: EXT: Re: Create Dataframe from a single String in Java
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You can call that on sparkSession to
On Thu, 18 Nov 2021, 10:48
You can call that on sparkSession to
On Thu, 18 Nov 2021, 10:48 , wrote:
> PS: The following works, but it seems rather awkward having to use the
> SQLContext here.
>
> SQLContext sqlContext = new SQLContext(sparkContext);
>
> Dataset data = sqlContext
> .createDataset(textList, Encoders.S
The most convenient way I'm aware of from Java is to use createDataset and
pass Encoder.String
That gives you a Dataset if you still want Dataset the you can
call .toDF on it
On Thu, 18 Nov 2021, 10:27 , wrote:
> Hello,
>
> I am struggling with a task that should be super simple: I would like t
PS: The following works, but it seems rather awkward having to use the
SQLContext here.
SQLContext sqlContext = new SQLContext(sparkContext);
Dataset data = sqlContext
.createDataset(textList, Encoders.STRING())
.withColumnRenamed("value", "text");
Am 2021-11-18 11:26, schrieb mar.
Hello,
I am struggling with a task that should be super simple: I would like to
create a Spark DF of Type Dataset with one column from a single
String (or from a one-element List of Strings). The column header should
be "text".
SparkContext.parallelize() does not work, because it returns RDD
