Solodovnik
Cc: Openmeetings user-list
Oggetto: Re: Bandwidth calculation
Hello, Dario.
First of all, let's clarify the real situation - 2 participans only with audio
(44Kbit/s):
SERVER INBOUND : 44Kbit/s for each participant => 44Kbit/s * 2 => 88Kbit/s
SERVER OUTBOUND : 44Kbit/s for each
tecipant => 44Kbit/s * 2 * 1 =>
>> 88Kbit/s (TOTAL)
>>
>> CLIENT INBOUND : 44Kbit/s (44Kbit/s because I receive only the stream of
>> the other …my stream is local from my webcam)
>>
>> CLIENT OUTBOUND : 44Kbit/s (my stream)
>>
>>
>>
>&g
im Solodovnik [mailto:solomax...@gmail.com]
> *Inviato:* giovedì 26 febbraio 2015 15:50
> *A:* Openmeetings user-list
> *Oggetto:* Re: Bandwidth calculation
>
>
>
> each of 2 participants receives 2 streams, 1 for him/herself and one for
> other party
>
>
>
> On Thu
ilto:solomax...@gmail.com]
Inviato: giovedì 26 febbraio 2015 15:50
A: Openmeetings user-list
Oggetto: Re: Bandwidth calculation
each of 2 participants receives 2 streams, 1 for him/herself and one for other
party
On Thu, Feb 26, 2015 at 8:13 PM, Dario Guida
wrote:
Why for each Parteci
each of 2 participants receives 2 streams, 1 for him/herself and one for
other party
On Thu, Feb 26, 2015 at 8:13 PM, Dario Guida <
produzion...@infotelsistemi.com> wrote:
> Why for each Partecipant inbound bandwidth is 88 Kbit/s …..
>
> If server send 88Kbit/s (total)
>
> Partecipant 1 receive :
Why for each Partecipant inbound bandwidth is 88 Kbit/s ...
If server send 88Kbit/s (total)
Partecipant 1 receive : 44Kbit/s
Partecipant 2 receive : 44Kbit/s
So Partecipant inbound bandwidth is 44 Kbit/s
