Re: hadoop results

2011-06-30 Thread William Oberman
I think I'll do the former, thanks! On Wed, Jun 29, 2011 at 11:16 PM, aaron morton wrote: > How about get_slice() with reversed == true and count = 1 to get the > highest time UUID ? > > Or you can also store a column with a magic name that have the value of the > timeuuid that is the current me

Re: hadoop results

2011-06-29 Thread aaron morton
How about get_slice() with reversed == true and count = 1 to get the highest time UUID ? Or you can also store a column with a magic name that have the value of the timeuuid that is the current metric to use. Cheers - Aaron Morton Freelance Cassandra Developer @aaronmorton h

hadoop results

2011-06-29 Thread William Oberman
I'll start with my question: given a CF with comparator TimeUUIDType, what is the most efficient way to get the greatest column's value? Context: I've been running cassandra for a couple of months now, so obviously it's time to start layering more on top :-) In my test environment, I managed to g