On Thu, Jul 7, 2011 at 3:39 PM, A J wrote:
> Thanks. The above works.
> But when I try to use the binary values rather than the hex values, it
> does not work. i.e. instead of using 64ff, I use 01100100. Instead of
> 6Dff, I use 01101101.
> When using the binary values, everything (strings startin
Thanks. The above works.
But when I try to use the binary values rather than the hex values, it
does not work. i.e. instead of using 64ff, I use 01100100. Instead of
6Dff, I use 01101101.
When using the binary values, everything (strings starting with a to
z) seem to be going to n1 only.
Any idea w
On Wed, Jul 6, 2011 at 3:06 PM, A J wrote:
> I wish to use the order preserving byte-ordered partitioner. How do I
> figure the initial token values based on the text key value.
> Say I wish to put all keys starting from a to d on N1. e to m on N2
> and n to z on N3. What would be the initial_toke
I wish to use the order preserving byte-ordered partitioner. How do I
figure the initial token values based on the text key value.
Say I wish to put all keys starting from a to d on N1. e to m on N2
and n to z on N3. What would be the initial_token values on each of
the 3 nodes to accomplish this ?
