Apparently the MemTable..writeSortedContents has the same problem: I can
see how it iterates over the stored keys in byte order, so my classes have
something wrong. For the curious, these are my classes until now:
https://gist.github.com/anonymous/5261611
Carlos Pérez Miguel
2013/3/28 aaron
er_id: eac850fa-96f4-11e2-9f22-72ad6af0e500 name:"a"
user_id: f17f9ae8-96f4-11e2-98aa-421151417092 name:"b"
user_id: f82fccfa-96f4-11e2-8d99-26f8461d074c name:"c"
user_id: fee21cec-96f4-11e2-945b-f9a2a2e32308 name:"d"
Any idea what's happening?
Car
Yes it does. Thank you Aaron.
Now I realized that the system keyspace uses string as keys, like "Ring" or
"ClusterName", and I don't know how to convert these type of keys into
UUID. Any idea?
Carlos Pérez Miguel
2013/3/25 aaron morton
> The best thing t
custom Partitioner in order to do this. If I use ByteOrderedPartitioner
rows are not correctly ordered because of the way a UUID stores the
timestamp. What is needed in order to implement my own Partitioner?
Thank you.
Carlos Pérez Miguel
a, ok. Now I understand where the data came from. When using CL.ALL
read_repair always repairs inconsistent data.
Thanks a lot, Sylvain.
Carlos Pérez Miguel
2013/1/17 Sylvain Lebresne
> You're missing the correct definition of read_repair_chance.
>
> When you do a read
te get KS1.CF1['data1'] with consistency level ALL -> still return
the correct data!
Where did that data come from? the endpoint is supposed to be empty of
data. I tried this using cassandra-cli and cassandra's ruby client and the
result is always the same. What did I miss?
Thank you for reading until the end, ;)
Bye
Carlos Pérez Miguel
not be in
the range [0, (2**128)-1]?
Anyway, if Cassandra uses only 127 bits of that 128 bits because it
tries to convert this 128 bit into a signed int, tokens should not be
in the range [0, 2**127) (first limit included, last not included)?
Thank you
Carlos Pérez Miguel
your cassandra.yaml file.
If you execute it and there is already a schema in the cassandra
cluster, you'll get a exception from schematool but no impact to the
cluster.
Bye
Carlos Pérez Miguel
2012/1/17 Ramesh Natarajan :
> I usually start cassandra and then use cassandra-cli to
Sorry, my english is not very well on sundays. By "partage" i mean "to
share" and by greate I mean "great".
Anyway, thanks everybody for your answers.
Carlos Pérez Miguel
El día 15 de enero de 2012 21:53, Carlos Pérez Miguel
escribió:
> If you can partage it
If you can partage it would be greate
Carlos Pérez Miguel
2012/1/15 Віталій Тимчишин :
> Yep. Have written groovy script this friday to perform autobalancing :) I am
> going to add it to my jenkins soon.
>
>
> 2012/1/15 Maxim Potekhin
>>
>> I see. Sure, that's
Thanks David for your explanation. What happens if autobootstrap is
false in the configuration file? nodes seem to choose the correct
token and balance well the cluster. In this case, how did each node to
select its initial token?
Carlos Pérez Miguel
2012/1/13 David McNelis :
>
node has initial token, nor
autobootstraping. I restart the cluster with each test I want to make
and in the end the cluster is always well balanced.
Thanks
Carlos Pérez Miguel
its token it means that no collision is possible, isn't
it?
Thank you
Carlos Pérez Miguel
2011/12/20 Brandon Williams :
> On Tue, Dec 20, 2011 at 2:24 PM, aaron morton wrote:
>> Sorry, got that a little wrong.
>>
>> At startup the node will use the higher of the c
process?
- Or it will be ignored or reconnected with another token?
- And what if it has changed its IP?
Thank you
Carlos Pérez Miguel
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