AJ was responding to an email I sent in Marchalthough i do appreciate
the quick reaponse from the community ;) i moved on to our implementation of
vpn...
On Jun 14, 2011 1:35 AM, "aaron morton" wrote:
> Sasha does
https://github.com/apache/cassandra/blob/cassandra-0.8.0/conf/cassandra.yaml#L36
Count of the columns in a row, not an exact count as that would requiring
stopping clients from writing to the row and we do not do that.
Have a poke around
http://www.datastax.com/docs/0.8/data_model/index
and
http://wiki.apache.org/cassandra/DataModel
Or are you asking about counter columns
Sasha does
https://github.com/apache/cassandra/blob/cassandra-0.8.0/conf/cassandra.yaml#L362
help ?
A
-
Aaron Morton
Freelance Cassandra Developer
@aaronmorton
http://www.thelastpickle.com
On 13 Jun 2011, at 23:26, AJ wrote:
> Performance-wise, I think it would be better to j
From a quick read of the code in o.a.c.db.ColumnFamilyStore.scan()...
Candidate rows are first read by applying the most selected equality predicate.
From those candidate rows...
1) If the SlicePredicate has a SliceRange the query execution will read all
columns for the candidate row if the b
You may also have been running into
https://issues.apache.org/jira/browse/CASSANDRA-2765. We'll have a fix
for this in 0.8.1.
2011/6/13 Héctor Izquierdo Seliva :
> I was already way over the minimum. There were 12 sstables. Also, is
> there any reason why scrub got stuck? I did not see anything in
I'm just becoming aware of the restrictions of using an OPP as compared
to Random. Please let me know if I understand this correctly.
First off, if using the OPP only for an increased performance of range
queries, then it will probably be very hard to predict if you will end
up with hotspots
Thanks! This clarifies a few things :)
On Mon, Jun 13, 2011 at 4:09 PM, wrote:
> Cleanup removes any data that node is no longer responsible for, according
> to the node's token range. A node can have data it is no longer responsible
> for if you do certain maintenance operations like move or lo
Cleanup removes any data that node is no longer responsible for, according
to the node's token range. A node can have data it is no longer responsible
for if you do certain maintenance operations like move or loadbalance.
On , Sebastien Coutu wrote:
How about cleanups? What would be the diff
It's a column whose content represents a distributed counter.
http://wiki.apache.org/cassandra/Counters
On Mon, Jun 13, 2011 at 8:29 AM, Sijie YANG wrote:
> Hi, All
>
> I am newbie to cassandra. I have a simple question but don't find any clear
> answer by searching google:
> What's the meaning
ok, I think it's better to understand it this way, then it is really simple
and intuitive:
my proposed way of counter update can be simply seen as a combination of
regular columns + current counter columns:
regular column : [ value: "wipes out every bucket to nil" , clock: epoch
number]
then w
How about cleanups? What would be the difference between cleanup and
compactions?
On Sat, Jun 11, 2011 at 8:14 AM, Jonathan Ellis wrote:
> Yes.
>
> On Sat, Jun 11, 2011 at 6:08 AM, Jonathan Colby
> wrote:
> > I've been reading inconsistent descriptions of what major and minor
> compactions do.
I think this approach also works for your scenario:
I thought that the issue is only concerned with merging within the same
leader; but you pointed out
that a similar merging happens between leaders too, now I see that the same
rules on epoch number
also applies to inter-leader data merging, speci
On 6/13/2011 10:14 AM, Stephen Connolly wrote:
store the query inverted.
that way empty -> deleted
I don't know what that means... get the other columns? Can you
elaborate? Is there docs for this or is this a hack/workaround?
the tombstones are stored for each column that had data IIRC.
On 13 June 2011 17:09, AJ wrote:
> On 6/13/2011 9:25 AM, Stephen Connolly wrote:
>>
>> On 13 June 2011 16:14, AJ wrote:
>>>
>>> On 6/13/2011 7:03 AM, Stephen Connolly wrote:
It returns the set of columns for the set of rows... how do you
determine the difference between a completel
On 6/13/2011 9:25 AM, Stephen Connolly wrote:
On 13 June 2011 16:14, AJ wrote:
On 6/13/2011 7:03 AM, Stephen Connolly wrote:
It returns the set of columns for the set of rows... how do you
determine the difference between a completely empty row and a row that
just does not have any of the matc
I don't think that's bulletproof either. For instance, what if the
two adds go to replica 1 but the delete to replica 2?
Bottom line (and this was discussed on the original
delete-for-counters ticket,
https://issues.apache.org/jira/browse/CASSANDRA-2101), counter deletes
are not fully commutative
as https://issues.apache.org/jira/browse/CASSANDRA-2101
indicates, the problem with counter delete is in scenarios like the
following:
add 1, clock 100
delete , clock 200
add 2 , clock 300
if the 1st and 3rd operations are merged in SStable compaction, then we
have
delete clock 200
add 3, clo
If you set key_start and key_finish to empty strings then you will get
all rows. You can do this with either RP or OPP, although with RP
they will not be returned in order.
--
Richard Low
Acunu | http://www.acunu.com | @acunu
On Mon, Jun 13, 2011 at 2:31 PM, Amrita Jayakumar
wrote:
> can u tel
probably helpful if you change the subject when posting about a
different topic.
Is your question about "counters" or the "count" function?
Counters are cool.
Count allows you to determine how many columns exist in a row.
-sd
On Mon, Jun 13, 2011 at 5:27 PM, Sijie YANG wrote:
> Hi, All
> I am
As Terje already said in this thread, the threshold is per bucket
(group of similarly sized sstables) not per CF.
2011/6/13 Héctor Izquierdo Seliva :
> I was already way over the minimum. There were 12 sstables. Also, is
> there any reason why scrub got stuck? I did not see anything in the
> logs.
Hi, All
I am newbie to cassandra. I have a simple question but don't find any clear
answer by searching google:
What's the meaning of counter column in Cassandra?
Best
Hi, All
I am newbie to cassandra. I have a simple question but don't find any clear
answer by searching google:
What's the meaning of count column in Cassandra? Thanks.
On 13 June 2011 16:14, AJ wrote:
> On 6/13/2011 7:03 AM, Stephen Connolly wrote:
>>
>> It returns the set of columns for the set of rows... how do you
>> determine the difference between a completely empty row and a row that
>> just does not have any of the matching columns?
>
> I would expect it
On 6/13/2011 7:03 AM, Stephen Connolly wrote:
It returns the set of columns for the set of rows... how do you
determine the difference between a completely empty row and a row that
just does not have any of the matching columns?
I would expect it to not return anything (no row at all) for both
I was already way over the minimum. There were 12 sstables. Also, is
there any reason why scrub got stuck? I did not see anything in the
logs. Via jmx I saw that the scrubbed bytes were equal to one of the
sstables size, and it stuck there for a couple hours .
El lun, 13-06-2011 a las 22:55 +0900,
hm. that's not it. we've been using a non-standard jmx port for some time
i've dropped the keyspace and recreated ...
wonder if that'll help
On Mon, Jun 13, 2011 at 3:57 PM, Tyler Hobbs wrote:
> On Mon, Jun 13, 2011 at 8:41 AM, Sasha Dolgy wrote:
>>
>> I recall there being a discussion a
On Mon, Jun 13, 2011 at 8:41 AM, Sasha Dolgy wrote:
> I recall there being a discussion about a default port changing from
> 0.7.x to 0.8.x ...this was JMX, correct? Or were there others.
>
Yes, the default JMX port changed from 8080 to 7199. I don't think there
were any others.
--
Tyler Hob
That most likely happened just because after scrub you had new files and got
over the "4" file minimum limit.
https://issues.apache.org/jira/browse/CASSANDRA-2697
Is the bug report.
2011/6/13 Héctor Izquierdo Seliva
> Hi All. I found a way to be able to compact. I have to call scrub on
> the
I recall there being a discussion about a default port changing from
0.7.x to 0.8.x ...this was JMX, correct? Or were there others.
On Mon, Jun 13, 2011 at 3:34 PM, Sasha Dolgy wrote:
> Hi Aaron,
>
> The error is being reported on all 4 nodes. I have confirmed (for my
> own sanity) that each nod
Hi Aaron,
The error is being reported on all 4 nodes. I have confirmed (for my
own sanity) that each node is running: ReleaseVersion: 0.8.0
I can reproduce the error on any node by trailing
cassandra/logs/system.log and running "nodetool repair"
INFO [manual-repair-1c6b33bc-ef14-4ec8-94f6-f146
can u tell me how to retrieve all the row keys in a column family???
On Mon, Jun 13, 2011 at 6:25 PM, Dan Kuebrich wrote:
> Are you using the order preserving partitioner or the random partitioner
> for this CF? In order to get the results you expect, you'll need to use the
> OPP.
>
> More info:
It returns the set of columns for the set of rows... how do you
determine the difference between a completely empty row and a row that
just does not have any of the matching columns?
Well the answer is that Cassandra does not go and check whether there
are any columns outside of the range you are
You can double check with node tool e.g.
$ ./bin/nodetool -h localhost version
ReleaseVersion: 0.8.0-SNAPSHOT
This error is about the internode wire protocol one node thinks another is
using. Not sure how it could get confused, does it go away if you restart the
node that logged the error ?
http://wiki.apache.org/cassandra/FAQ#range_ghosts
"So to special case leaving out result entries for deletions, we would
have to check the entire rest of the row to make sure there is no
undeleted data anywhere else either (in which case leaving the key out
would be an error)."
The above doe
Hi All. I found a way to be able to compact. I have to call scrub on
the column family. Then scrub gets stuck forever. I restart the node,
and voila! I can compact again without any message about not having
enough space. This looks like a bug to me. What info would be needed to
fill a report? This
Are you using the order preserving partitioner or the random partitioner for
this CF? In order to get the results you expect, you'll need to use the
OPP.
More info:
http://ria101.wordpress.com/2010/02/22/cassandra-randompartitioner-vs-orderpreservingpartitioner/
On Mon, Jun 13, 2011 at 8:47 AM,
Hi,
I am trying to retrieve the row_keys in a column_family witht he following
code.
$rows = $column_family->get_range($key_start='R17889000',
$key_finish='R17893999', $row_count=1000);
$count = 0;
foreach($rows as $rows) {
echo $count.'';
$count += 1;
To reduce the number of SSTables increase the memtable_threshold for the CF.
The IO numbers may be because of compaction kicking in. The CompactionManager
provides information via JMX on it's progress, or you can check the logs. You
could increase the min_compaction_threshold for the CF or disa
Performance-wise, I think it would be better to just let the client
encrypt sensitive data before storing it, versus encrypting all traffic
all the time. If individual values are encrypted, then they don't have
to be encrypted/decrypted during transit between nodes during the
initial updates a
On Sun, 2011-06-12 at 18:53 +, Mick Semb Wever wrote:
> > This issue could stand to be summarized (I still wish we used a
> > mailing list for monsters like this).
>
>
> This i actually really appreciate about the cassandra community.
To formulate this: As a newbie here it has allowed me to
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