Hi,
following skript-part download package of files to make some diffs.
Download von ${host}
This days a problem gets up.
In the directory are some linked-files.
Following error resulted:
BUILD FAILED
C:\workspace\Synchro - Tool\Monitori
Hi out there,
is it possible to get only the name of a file without the whole path??
This is for path - but only need the filename:
@{filename}
The files are in a directory!!
Regards ele
CTED]>:
Try this:
Filename === ${filename}
Notice the element has the attribute unset="true"
Benjamin H. wrote:
> I has try this:
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I has try this:
Filename === ${filename}
But not so successful!!
2006/8/17, Scot P. Floess <[EMAIL PROTECTED]>:
Did you try the task?
Benj
Hi out there,
is it possible to get only the name of a file without the whole path??
This is for path - but only need the filename:
@{filename}
The files are in a directory!!
Regards ele
