On Jan 14, 2016, at 6:06 AM, Ben Rubinstein wrote:
> So if the device is vertical at rest (y=-1), and falls down vertically, it
> won't register any acceleration because it's already measuring the maximum in
> that axis?
>
> In short, it's static acceleration rather than dynamic acceleration, i
On Jan 14, 2016, at 6:06 AM, Ben Rubinstein wrote:
> So if the device is vertical at rest (y=-1), and falls down vertically, it
> won't register any acceleration because it's already measuring the maximum in
> that axis?
>
> In short, it's static acceleration rather than dynamic acceleration, i
Hopefully, I've got this right but.
I think of it as the "apparent" acceleration a mass attached to phone feels
relative to the body of the device. At rest, if it wasn't attached, it would
slide down the inside of the device and end up rattling inside the case. The
force trying to make that
Thanks Jim.
So if the device is vertical at rest (y=-1), and falls down vertically, it
won't register any acceleration because it's already measuring the maximum in
that axis?
In short, it's static acceleration rather than dynamic acceleration, is that
correct?
Many thanks,
Ben
On 13/01
Short answer: Gravity.
The device can't measure actual acceleration. It measures the forces on
sensors in 3 axes. One of those axes will feel force from gravity. That's
the 1.
Jim
-Original Message-
From: Ben Rubinstein [mailto:benr...@cogapp.com]
Sent: Wednesday, January 13, 2016 5:08 A