On 6/25/19 8:46 PM, Brian Milby via use-livecode wrote:
Nothing gets put into limbo. The pointer is deleted/removed from the array
thus reducing the reference count held by the object containing the value. In
the above example, the only pointer left is the one held by tSubArray until a
copy
Nothing gets put into limbo. The pointer is deleted/removed from the array
thus reducing the reference count held by the object containing the value. In
the above example, the only pointer left is the one held by tSubArray until a
copy of the pointer is placed in the array as the new key which
On 6/25/19 4:31 PM, Brian Milby via use-livecode wrote:
Value object starts with a ref count of 1 in the array
The first put increases the ref count to 2
The delete takes it back to 1
The second put takes it back to 2
At the end of the handler it goes back to 1 since the local var goes away
Mmm
Value object starts with a ref count of 1 in the array
The first put increases the ref count to 2
The delete takes it back to 1
The second put takes it back to 2
At the end of the handler it goes back to 1 since the local var goes away
Thanks,
Brian
On Jun 25, 2019, 6:35 PM -0400, Mark Wieder via
On 6/25/19 1:25 AM, Mark Waddingham via use-livecode wrote:
On 2019-06-25 04:18, Brian Milby via use-livecode wrote:
My guess is that it has to do with the copy on write property of
arrays. If you used your method it may force an actual duplication.
The existing method just passes a pointer ef
:-)
> On Jun 24, 2019, at 20:55 , J. Landman Gay via use-livecode
> wrote:
>
> I love when you guys talk geek to me. "Tell me more about my
> arrays."
>
> https://youtu.be/dEaFFZpfxLU
>
> --
> Jacqueline Landman Gay | jac...@hyperactivesw.com
__
On 2019-06-25 04:18, Brian Milby via use-livecode wrote:
My guess is that it has to do with the copy on write property of
arrays. If you used your method it may force an actual duplication.
The existing method just passes a pointer effectively. I could be
totally wrong though.
On Jun 24, 2019
I love when you guys talk geek to me. "Tell me more about my
arrays."
https://youtu.be/dEaFFZpfxLU
--
Jacqueline Landman Gay | jac...@hyperactivesw.com
HyperActive Software | http://www.hyperactivesw.com
On June 24, 2019 9:44:55 PM Mark Wieder via use-livecode
wrote:
On 6/24/19 7:18 PM, B
On 6/24/19 7:18 PM, Brian Milby via use-livecode wrote:
My guess is that it has to do with the copy on write property of arrays. If
you used your method it may force an actual duplication. The existing method
just passes a pointer effectively. I could be totally wrong though.
Dunno. Possib
My guess is that it has to do with the copy on write property of arrays. If
you used your method it may force an actual duplication. The existing method
just passes a pointer effectively. I could be totally wrong though.
Thanks,
Brian
On Jun 24, 2019, 10:11 PM -0400, Mark Wieder via use-livec
On 6/24/19 7:00 PM, Brian Milby via use-livecode wrote:
Close, here's the actual code (part of setArrayKeyOnPath):
put xArray[item 1 of pPath] into tSubArray
delete variable xArray[item 1 of pPath]
put tSubArray into xArray[pKey]
Interesting. Wouldn't it be faster to do
p
Close, here's the actual code (part of setArrayKeyOnPath):
put xArray[item 1 of pPath] into tSubArray
delete variable xArray[item 1 of pPath]
put tSubArray into xArray[pKey]
I didn't specify the first step in my original answer. I only knew about
this because I had been looking
On 6/24/19 12:37 PM, Brian Milby via use-livecode wrote:
I’m pretty sure the PI deletes the old key and creates a new key with the
existing value.
I'm pretty sure (in this post-facts world I haven't actually looked)
it's the other way around: copy the existing contents into the new key,
*the
Thanks, I hadn't thought of just extracting a chunk of the array. I
should have.
On 6/24/19 2:37 PM, Brian Milby via use-livecode wrote:
I’m pretty sure the PI deletes the old key and creates a new key with the
existing value.
Thanks,
Brian
On Jun 24, 2019, 3:23 PM -0400, J. Landman Gay via u
I’m pretty sure the PI deletes the old key and creates a new key with the
existing value.
Thanks,
Brian
On Jun 24, 2019, 3:23 PM -0400, J. Landman Gay via use-livecode
, wrote:
> I have a multi-dimensional array and sometimes I need to change the text
> of one of the array keys without destroyin
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