Le vendredi 05 septembre 2008 à 08:14 +, Fournier Frédéric a écrit :
>
> Here is an algorithm that gives you the smallest denominator of a floating
> number written in the form of fraction.
> with that you can solve the problem even if in the calculation of x ^
> (n
Here is an algorithm that gives you the smallest denominator of a floating
number written in the form of fraction.
with that you can solve the problem even if in the calculation of x ^
(n / m), n / m is transformed into a floating because you can
find something iteration.
I use that frac refe
Le jeudi 04 septembre 2008 à 17:58 +, Fournier Frédéric a écrit :
>
> no, what should be done on a mathematical point of view, if you want to
> calculate x ^ (n / m), is to do a test of parity on m:
> if m is even then if x <0 I can not calculate x ^ (n / m) because
> comp
no, what should be done on a mathematical point of view, if you want to
calculate x ^ (n / m), is to do a test of parity on m:
if m is even then if x <0 I can not calculate x ^ (n / m) because
complex
if m is odd then if X <0 then the calculation becomes (-x) ^ (n / m)
Apply this method manual
it just me references: "value" and not -2
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Le mercredi 03 septembre 2008 à 14:56 +, Chris Coulson a écrit :
> Whats wrong with '(-8)^(1/3)=-2'?
>
> If you work back the other way (ie '(-2)^3'), we get (-2)*(-2)*(-2)=-8,
> so this is correct
>
> ** Changed in: openoffic
Public bug reported:
Binary package hint: openoffice.org
=> Valeur!
h???
=(-8)^(1/3)=-2
sorry je ne parle pas anglais...
** Affects: openoffice.org (Ubuntu)
Importance: Undecided
Status: New
--
=(-8)^(1/3)
https://bugs.launchpad.net/bugs/264345
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