On Fri, Jan 11, 2013 at 7:35 AM, Marek Vasut wrote:
> In case a function argument is known/fixed size array in C, the argument is
> still decoyed as pointer instead ( T f(U n[k]) ~= T fn(U *n) ) and therefore
> calling sizeof on the function argument will result in the size of the
> pointer,
> no
Marek Vasut denx.de> wrote:
> In case a function argument is known/fixed size array in C, the argument is
> still decoyed as pointer instead ( T f(U n[k]) ~= T fn(U *n) ) and therefore
> calling sizeof on the function argument will result in the size of the
> pointer,
> not the size of the array.
2013/1/11 Marek Vasut :
> In case a function argument is known/fixed size array in C, the argument is
> still decoyed as pointer instead ( T f(U n[k]) ~= T fn(U *n) ) and therefore
> calling sizeof on the function argument will result in the size of the
> pointer,
> not the size of the array.
>
>
In case a function argument is known/fixed size array in C, the argument is
still decoyed as pointer instead ( T f(U n[k]) ~= T fn(U *n) ) and therefore
calling sizeof on the function argument will result in the size of the pointer,
not the size of the array.
The VFAT code contains such a bug, thi
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