Dear Larry Johnson,
In message <49a177d8.1050...@acm.org> you wrote:
>
> > Although load address and image start address are same address,
> > bootm command always does memmove.
> > That is unnecessary memmove and can be taken few milliseconds
> > (about 500 msec to 1000 msec).
> > If skip this me
Minkyu Kang wrote:
> Although load address and image start address are same address,
> bootm command always does memmove.
> That is unnecessary memmove and can be taken few milliseconds
> (about 500 msec to 1000 msec).
> If skip this memmove, we can reduce the boot time.
>
> Signed-off-by: Minkyu
Dear Minkyu Kang,
In message <499b50e0.8040...@samsung.com> you wrote:
> Although load address and image start address are same address,
> bootm command always does memmove.
> That is unnecessary memmove and can be taken few milliseconds
> (about 500 msec to 1000 msec).
> If skip this memmove, we
Although load address and image start address are same address,
bootm command always does memmove.
That is unnecessary memmove and can be taken few milliseconds
(about 500 msec to 1000 msec).
If skip this memmove, we can reduce the boot time.
Signed-off-by: Minkyu Kang
---
common/cmd_bootm.c |
Dear Minkyu Kang,
In message <499a676c.90...@samsung.com> you wrote:
> Although load address and image start address are same address, bootm command
> does memmove.
> That is unnecessary memmove and can be taken few milliseconds (about 500 msec
> to 1000 msec).
> If reduce this memmove, we can r
Although load address and image start address are same address, bootm command
does memmove.
That is unnecessary memmove and can be taken few milliseconds (about 500 msec
to 1000 msec).
If reduce this memmove, we can reduce the boot time.
Please check this patch.
Thank you.
Minkyu Kang.
Signed
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