Would be great to have a follow up for all those of us who couldn't attend for
various reasons?
Paul
Am 26.12.18 um 21:36 schrieb Alexander Dietrich:
> Another update: we have moved the meetup to 2018-12-28 (Day 2), 12:00:
> https://events.ccc.de/congress/2018/wiki/index.php/Session:Tor_relay_o
Another update: we have moved the meetup to 2018-12-28 (Day 2), 12:00:
https://events.ccc.de/congress/2018/wiki/index.php/Session:Tor_relay_operators_meetup
Kind regards,
Alexander
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PGP Key: https://dietrich.cx/pgp | 0x52FA4EE1722D54EB
On 2018-12-24 23:16, 35C3 35C3 wrote:
On December 24, 20
> On December 24, 2018 at 10:58 PM 35C3 35C3 <3...@mailbox.org> wrote:
>
>
> > Hi, I have only my smartphone at the moment. It would be great if you swap
> > the rooms. Thank you
>
> added a second slot on the first day/night:
> 2018-12-28 00:30
> Room M3
>
> I did NOT replace the first slot
> Hi, I have only my smartphone at the moment. It would be great if you swap
> the rooms. Thank you
added a second slot on the first day/night:
2018-12-28 00:30
Room M3
I did NOT replace the first slot in the smaller room (2018-12-28 16:30) because
the second slot
is a bit late to avoid colli
thanks for adding it.
> since the number of rooms is very limited, I have reserved a slot for
> the Relays Operators Meetup: 2018/12/27 16:30, 90 minutes, lecture room
> M2. The room has 48 seats and a beamer.
Last year we had room 11 with 100 seats and it was packed
so I think that 48 seats m
Hi all,
>
> If so, it would be great if we could get
> - a slightly bigger room than we had last year
> - a room with a beamer
>
since the number of rooms is very limited, I have reserved a slot for
the Relays Operators Meetup: 2018/12/27 16:30, 90 minutes, lecture room
M2. The room has 48 seats
Hi nicoo,
since you organized the tor relay operators meetups
during the last few years at the CCC I was wondering if you will
continue with that this year as well?
If so, it would be great if we could get
- a slightly bigger room than we had last year
- a room with a beamer
(Roger will not be
