Re: [SR-Users] Syntax of xavp

2012-12-12 Thread Olle E. Johansson
12 dec 2012 kl. 11:11 skrev Daniel-Constantin Mierla : > > On 12/12/12 11:08 AM, Olle E. Johansson wrote: >> >> 12 dec 2012 kl. 10:44 skrev Daniel-Constantin Mierla : >> >>> Hello, >>> >>> On 10/9/12 3:59 PM, Andreas Granig wrote: Hi, I'm playing around with xavp, but there ar

Re: [SR-Users] Syntax of xavp

2012-12-12 Thread Daniel-Constantin Mierla
On 12/12/12 11:08 AM, Olle E. Johansson wrote: 12 dec 2012 kl. 10:44 skrev Daniel-Constantin Mierla mailto:mico...@gmail.com>>: Hello, On 10/9/12 3:59 PM, Andreas Granig wrote: Hi, I'm playing around with xavp, but there are some things I can't wrap my head around. What basically works

Re: [SR-Users] Syntax of xavp

2012-12-12 Thread Olle E. Johansson
12 dec 2012 kl. 10:44 skrev Daniel-Constantin Mierla : > Hello, > > On 10/9/12 3:59 PM, Andreas Granig wrote: >> Hi, >> >> I'm playing around with xavp, but there are some things I can't wrap my >> head around. >> >> What basically works is this: >> >> $xavp(a=>foo) = 'foo'; >> $xavp(a[0]=>ba

Re: [SR-Users] Syntax of xavp

2012-12-12 Thread Daniel-Constantin Mierla
Hello, On 10/9/12 3:59 PM, Andreas Granig wrote: Hi, I'm playing around with xavp, but there are some things I can't wrap my head around. What basically works is this: $xavp(a=>foo) = 'foo'; $xavp(a[0]=>bar) = 'bar'; Getting the value like this: xlog("L_INFO", "a-foo='$xavp(a=>foo)' and a-b

[SR-Users] Syntax of xavp

2012-10-09 Thread Andreas Granig
Hi, I'm playing around with xavp, but there are some things I can't wrap my head around. What basically works is this: $xavp(a=>foo) = 'foo'; $xavp(a[0]=>bar) = 'bar'; Getting the value like this: xlog("L_INFO", "a-foo='$xavp(a=>foo)' and a-bar='$xavp(a=>bar)'"); as well as xlog("L_INFO", "a-f