On 10/04/2011 01:25 PM, Yonit Halperin wrote:
On 10/04/2011 01:20 PM, Alon Levy wrote:
On Tue, Oct 04, 2011 at 01:00:47PM +0200, Alon Levy wrote:
On Tue, Oct 04, 2011 at 12:40:21PM +0200, Yaniv Kaul wrote:
Unless I'm misreading the code (which may very well be), the
function looks like:
if (m
On 10/04/2011 01:20 PM, Alon Levy wrote:
On Tue, Oct 04, 2011 at 01:00:47PM +0200, Alon Levy wrote:
On Tue, Oct 04, 2011 at 12:40:21PM +0200, Yaniv Kaul wrote:
Unless I'm misreading the code (which may very well be), the
function looks like:
if (mask_bitmap&& m) {
if (this or that) {
On Tue, Oct 04, 2011 at 01:00:47PM +0200, Alon Levy wrote:
> On Tue, Oct 04, 2011 at 12:40:21PM +0200, Yaniv Kaul wrote:
> > Unless I'm misreading the code (which may very well be), the
> > function looks like:
> >
> > if (mask_bitmap && m) {
> > if (this or that) {
> > do X
> >
On 10/04/2011 01:00 PM, Alon Levy wrote:
On Tue, Oct 04, 2011 at 12:40:21PM +0200, Yaniv Kaul wrote:
Unless I'm misreading the code (which may very well be), the
function looks like:
if (mask_bitmap&& m) {
if (this or that) {
do X
fill_bits(...)
} else {
fi
On Tue, Oct 04, 2011 at 12:40:21PM +0200, Yaniv Kaul wrote:
> Unless I'm misreading the code (which may very well be), the
> function looks like:
>
> if (mask_bitmap && m) {
> if (this or that) {
> do X
> fill_bits(...)
> } else {
> fill_bits(...)
> }
> }
>
> S
Unless I'm misreading the code (which may very well be), the function
looks like:
if (mask_bitmap && m) {
if (this or that) {
do X
fill_bits(...)
} else {
fill_bits(...)
}
}
So essentially, if the condition (mask_bitmap && m) is NOT met, we do
not fill the b
