Hi,
I would use something like:
for (i=0; i<4; i++)
char_counter[i] = ((unsigned char*)&long_counter)[i];
for (i=0; i<4; i++)
((unsigned char*)&long_counter)[i] = char_counter[i];
Hynek
Dne 4.5.2011 4:08, stof...@skulp.net napsal(a):
Hi, I have to transmit an unsigned long as four bytes
On Wed, 4 May 2011, Kevin Bailey wrote:
On Wed, May 4, 2011 at 7:31 PM, Erik Petrich
wrote:
long_counter = (unsigned int)(char_counter[0] | (char_counter[1] << 8)) |
((unsigned long)(char_counter[2] | (char_counter[3] << 8)) << 16);
I hope the first (unsigned int) cast isn't necessar
On Wed, May 4, 2011 at 7:31 PM, Erik Petrich
wrote:
>
>
> long_counter = (unsigned int)(char_counter[0] | (char_counter[1] << 8)) |
> ((unsigned long)(char_counter[2] | (char_counter[3] << 8)) << 16);
I hope the first (unsigned int) cast isn't necessary, because the
char_counter[1] << 8 wo
On Thu, 5 May 2011, Kristoffer Ek wrote:
>
> On 4.5.2011, at 6:20, Erik Petrich wrote:
>
>> long_counter = (char_counter[0] | (char_counter[1] << 8)) |
>> ((unsigned long)(char_counter[2] | (char_counter[3] << 8)) << 16);
>
>
> This overflows at 32767 :-/
>
> -- stoffer
Sorry, I didn't ta
On 4.5.2011, at 6:20, Erik Petrich wrote:
> long_counter = (char_counter[0] | (char_counter[1] << 8)) |
> ((unsigned long)(char_counter[2] | (char_counter[3] << 8)) << 16);
This overflows at 32767 :-/
-- stoffer
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