Sorry, I misunderstood your question which is harder (and more
interesting!) than I thought. I hope there will be some creative
suggestions.
John
On 2 April 2015 at 17:22, Pierre wrote:
> PS sorry i wrote
>
>> to be clear : i know there is at least a relation
>>
>> P_0(x) + P_1(x) f + P_2(x) f^
PS sorry i wrote
to be clear : i know there is at least a relation
>
> P_0(x) + P_1(x) f + P_2(x) f^2 + ... + P_d(x) f^d
>
i meant to end with " = 0 ".
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> Given a degree bound d in y, you are looking for a linear relation
> between 1, f, f^2, ..., f^d, which you could find using linear
> algebra over K after making sure that you have at least d+1
>
I'm looking for a linear relation with coefficients in K(x), so you
probably mean linear alge
On 2 April 2015 at 16:13, Pierre wrote:
> Hi,
>
> I have a power series f in K[[x]] where K is a finite field, and I know that
> it is algebraic over K(x). I'm looking for an explicit polynomial P in K[x,
> y] such that P(x, f) = 0. I can figure out a bound for the degree of P in y,
> in my exampl
Hi,
I have a power series f in K[[x]] where K is a finite field, and I know
that it is algebraic over K(x). I'm looking for an explicit polynomial P in
K[x, y] such that P(x, f) = 0. I can figure out a bound for the degree of P
in y, in my example (though not in x).
Given this post
https://g