On Apr 23, 2010, at 1:37 AM, bb wrote:
Mike Hansen schrieb:
On Mon, Apr 19, 2010 at 11:52 AM, bb wrote:
I get a runtime error, but just would expect infinity! Is there
something
wrong or any explanation?
This is because when you do 2^3^4^5 you are computing that number
exactly as an int
Mike Hansen schrieb:
On Mon, Apr 19, 2010 at 11:52 AM, bb wrote:
I get a runtime error, but just would expect infinity! Is there something
wrong or any explanation?
This is because when you do 2^3^4^5 you are computing that number
exactly as an integer, and that number is definitely n
On Mon, Apr 19, 2010 at 11:52 AM, bb wrote:
> I get a runtime error, but just would expect infinity! Is there something
> wrong or any explanation?
This is because when you do 2^3^4^5 you are computing that number
exactly as an integer, and that number is definitely not infinity. If
you wanted t
bb schrieb:
sage: 2^3^4^5
---
RuntimeError Traceback (most recent call
last)
/home/bb/sage-4.3.5/ in ()
/home/bb/sage-4.3.5/local/lib/python2.6/site-packages/sage/rings/integer.so
in sage.r
sage: 2^3^4^5
---
RuntimeError Traceback (most recent call last)
/home/bb/sage-4.3.5/ in ()
/home/bb/sage-4.3.5/local/lib/python2.6/site-packages/sage/rings/integer.so
in sage.rings.integer.Inte
