I'm not sure if this helps your situation or not, but if you are
interested in the roots of "f(x)=0", then using roots has a much more
predictable behaviour.
So for example:
sage: expr=(x^3+10*x^2+11*x+8)
sage: expr.roots()
sage: expr.roots(ring=RR)
[(-8.86042628425072, 1)]
sage: expr.roots(rin
Hi
thanks for your earlier answers.
I quite often do this:
sage: solve(x^3 + 10*x^2+11*x+8==0,x)
[snip]
Then I realize that the analytic solution is rather complicated.
So I want a numerical approximation.
I tried this:
roots = solve(x^3+10*x^2+11*x+8==0,x)
sage: roots
[x == -1/2*(1/3*sqrt(
Hi,
On Sun, 4 Jul 2010 05:36:50 -0700 (PDT)
dirkd wrote:
> Why is evaluating this expression problematical?
>
> y1(x)=x^2;y2(x)=5-x;
> a0=1;an=3;Delta=(an-a0)/n;p(k)=a0+(k-1/2)*Delta;
> I(n)=sum(abs(y2(p(k))-y1(p(k)))*Delta,k,1,n);
> N(I(10))
>
> SAGE respons:
> File "expression.pyx", line
Why is evaluating this expression problematical?
y1(x)=x^2;y2(x)=5-x;
a0=1;an=3;Delta=(an-a0)/n;p(k)=a0+(k-1/2)*Delta;
I(n)=sum(abs(y2(p(k))-y1(p(k)))*Delta,k,1,n);
N(I(10))
SAGE respons:
Traceback (most recent call last):
File "", line 1, in
File "_sage_input_109.py", line 9, in
open(
Dear all,
I would like to evaluate a symbolic equation containing an integral
numerically:
((integrate(250*cos(pi*x/180)^1.8 + 170.35,x,0,18)/a_v)(a_v=1)).n()
does not work. Is there a way of doing this? The real equation is a
lot longer than the above, so I am looking for a simple automatic way.
