Re: [sage-support] Solving logarithmic equations

BTW : sage: solve(1+2*log(x+1, 4)==2*log(x,2), x, to_poly_solve="force") [x == -sqrt(3) + 1, x == sqrt(3) + 1] HTH, ​ Le samedi 9 avril 2022 à 11:34:10 UTC+2, wdjo...@gmail.com a écrit : > On Sat, Apr 9, 2022 at 5:18 AM Paolo Robillos > wrote: > > > > Hi, > > > > I am trying to solve the fol

Re: [sage-support] Solving logarithmic equations

On Sat, Apr 9, 2022 at 5:18 AM Paolo Robillos wrote: > > Hi, > > I am trying to solve the following equation for x, 1+2log(x+1, 4)==2log(x,2) > > I entered in the input "(1+2log(x+1, > 4)==2log(x,2)).solve(x,algorithm='sympy', domain='all')" > > and the Output was "{𝑥∣𝑥∈ℂ∧−𝑥2log(2)+𝑒(𝑥+1)1log(2)=

[sage-support] Solving logarithmic equations

Hi, I am trying to solve the following equation for x, 1+2*log(x+1, 4)==2* log(x,2) I entered in the input "(1+2*log(x+1, 4)==2*log(x,2)).solve(x,algorithm='sympy', domain='all')" and the Output was "{𝑥∣𝑥∈ℂ∧−𝑥2log(2)+𝑒(𝑥+1)1log(2)=0}∖{𝑥∣𝑥∈ℂ∧𝑥2log(2)=0}" The answer I am looking for is "x =