On Jul 31, 2011, at 11:00 , William Stein wrote:
> On Sun, Jul 31, 2011 at 10:54 AM, Justin C. Walker wrote:
>>
>> On Jul 31, 2011, at 02:29 , tvn wrote:
>>
>>> The enumerate function in Python has the index type as 'int' instead of say
>>> sage's Integer. is there an equivalent of enumerat
Whoops, looks like William beat me to it.
On Mon, Aug 1, 2011 at 2:00 AM, Tim Joseph Dumol wrote:
> While I don't think there's one readily available, you can easily define
> one yourself:
>
> def senumerate(seq):
> return ((ZZ(i), x) for (i,x) in enumerate(seq))
>
> Hoep this helps.
>
>
> O
While I don't think there's one readily available, you can easily define one
yourself:
def senumerate(seq):
return ((ZZ(i), x) for (i,x) in enumerate(seq))
Hoep this helps.
On Sun, Jul 31, 2011 at 5:29 PM, tvn wrote:
> The enumerate function in Python has the index type as 'int' instead o
On Sun, Jul 31, 2011 at 10:54 AM, Justin C. Walker wrote:
>
> On Jul 31, 2011, at 02:29 , tvn wrote:
>
>> The enumerate function in Python has the index type as 'int' instead of say
>> sage's Integer. is there an equivalent of enumerate in Sage that returns
>> Integer type ? Thanks
>
> Try sra
On Jul 31, 2011, at 02:29 , tvn wrote:
> The enumerate function in Python has the index type as 'int' instead of say
> sage's Integer. is there an equivalent of enumerate in Sage that returns
> Integer type ? Thanks
Try srange and sxrange/xsrange.
Details with "?"
HTH
Justin
--
Justi
The enumerate function in Python has the index type as 'int' instead of say
sage's Integer. is there an equivalent of enumerate in Sage that returns
Integer type ? Thanks
--
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