Thanks for your help! Both solutions worked for me.
On Jun 16, 9:56 pm, "William Stein" <[EMAIL PROTECTED]> wrote:
> On Mon, Jun 16, 2008 at 9:43 AM, vpv <[EMAIL PROTECTED]> wrote:
>
> > Hello William,
>
> > Thanks for your reply! I think I can use your idea to solve my
> > problem. I tried to ru
On Mon, Jun 16, 2008 at 9:43 AM, vpv <[EMAIL PROTECTED]> wrote:
>
> Hello William,
>
> Thanks for your reply! I think I can use your idea to solve my
> problem. I tried to run your example in Sage for the case when
> x1,x2,x3,x5,x7 are in GF(2). I realized that in that case e1 and e2
> should also
There are probably more elegant ways to do this, but one way is:
varstring = ''
for i in range(1,101):
varstring += 'e' + str(i)+ ','
bool100 = eval('BooleanPolynomialRing(100,"' + varstring[0:-1] + '")')
-M. Hampton
On Jun 16, 10:43 am, vpv <[EMAIL PROTECTED]> wrote:
> Hello William,
>
>
Hello William,
Thanks for your reply! I think I can use your idea to solve my
problem. I tried to run your example in Sage for the case when
x1,x2,x3,x5,x7 are in GF(2). I realized that in that case e1 and e2
should also be defined in GF(2). As I need to do a hundred
substitutions in which all ei
On Sun, Jun 15, 2008 at 5:45 AM, vpv <[EMAIL PROTECTED]> wrote:
>
> I have two expressions - exp1 and exp2:
>
> sage: exp1 = (x1*x2+x3)
> sage: exp2 = (x1+x3*x5*x7)
> sage: exp1
> x1*x2 + x3
> sage: exp2
> x1 + x3*x5*x7
>
> I try to substitute exp1 and exp2 for the symbolic variables e1 and e2
> r
