On Jun 7, 2009, at 15:53 , amps wrote:
>
> When I say that n is not predetermined, I mean that I want my script
> to work for any n. So before I define the polynomial ring, n is
> determined, but I want this to work for all n. So my question is how
> do I do the following.
>
> n=6
> R=Polynomi
This works:
sage: n=6
sage: R=PolynomialRing(QQ,n,'z')
sage: z=R.gens()
sage: g=sum(z[i] for i in range(n))
sage: g.subs(dict((z[i], i) for i in range(n)))
15
--Mike
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On Jun 7, 2009, at 15:23 , amps wrote:
>
> sorry, i meant
>
> g.subs({z[1]:value1...})
>
> I am not sure why you call this intriguing syntax, but it is what
> works.
My turn to say sorry. I just mentally wiped out the '.subs' part.
> My problem is that I don't know how to do this if the numbe
When I say that n is not predetermined, I mean that I want my script
to work for any n. So before I define the polynomial ring, n is
determined, but I want this to work for all n. So my question is how
do I do the following.
n=6
R=PolynomialRing(QQ,n,'z')
z=R.gens()
g=sum(z[i] for i in range(n)
sorry, i meant
g.subs({z[1]:value1...})
I am not sure why you call this intriguing syntax, but it is what
works.
Example:
g=x+y
g.subs({x:2,y:4})
6
My problem is that I don't know how to do this if the number of
variables is not predetermined.
I tried to make a list with
a=list()
for i in rang
On Jun 7, 2009, at 13:03 , amps wrote:
>
> I want to substitute n values into polynomial with n variables.
>
> I guess the syntax to do this is (if g is my polynomial with
> indeterminates z[1], ..., z[n]).
>
> f.subs({z[1]:value1, z[2]:value2, ..., z[n]:valuen})
>
> but how do I actually do thi
