[sage-support] Re: sort a list

2009-07-15 Thread Simon King
Hi! On 15 Jul., 21:26, Carlos Córdoba wrote: > This is not about RTFM, because L1.sort() doesn't produce any result. It > just modifies the original list in place. ... and this is precisely what the manual tells you. However, you are right: > I think that Mikie wants to assign the sorted list

[sage-support] Re: sort a list

2009-07-15 Thread Mikie
Carlos, just what I needed. I have looked in scipy, but no Quartiles. On Jul 15, 1:26 pm, Carlos Córdoba wrote: > This is not about RTFM, because L1.sort() doesn't produce any result. It > just modifies the original list in place. > > I think that Mikie wants to assign the sorted list to another

[sage-support] Re: sort a list

2009-07-15 Thread Carlos Córdoba
This is not about RTFM, because L1.sort() doesn't produce any result. It just modifies the original list in place. I think that Mikie wants to assign the sorted list to another list. In that case what you need is the sorted command: sage: L1 = [56,2,4,10] sage: sort_L1 = sorted(L1) sage: sort_L1

[sage-support] Re: sort a list

2009-07-15 Thread Justin C. Walker
On Jul 15, 2009, at 12:14 , Mikie wrote: > > How does one sort a list in Sage? I have tried > > L1=[56,2,4,10] > Sort_ = L1.sort() > > and nothing is produced. As the saying goes, RTFM :-} sage: L1=[56,2,4,10] sage: L1.sort? Type: builtin_function_or_method Base Class: String F

[sage-support] Re: sort a list

2009-07-15 Thread Minh Nguyen
Hi Mikie, On Thu, Jul 16, 2009 at 5:14 AM, Mikie wrote: > > How does one sort a list in Sage? I have tried > > L1=[56,2,4,10] > Sort_ = L1.sort() > > and nothing is produced. Try this: -- | Sage Version 4.1, Release Date: 2009