[sage-support] Re: resultant for aite polynomials

2013-12-09 Thread Dominique Laurain
Newbie for that math subject...but... - there is one SAGE trac about Macaulay resultant: http://trac.sagemath.org/ticket/15382 ( SageDays 55?) - from Wikipedia I just got that Macaulay resultant is working for* homogenoeus* polynomials in n-variables - you can easily transform two bivariates

Re: [sage-support] Re: Resultant of two polynomials

2011-01-26 Thread Santanu Sarkar
Thank you. On 26 January 2011 18:20, John Cremona wrote: > > > On Jan 26, 8:09 am, Santanu Sarkar > wrote: >> I have two polynomials F(x,y,z) and G(x,y,z) over integer. From F, G I want >> to eliminate z by resultant method. How can I do this? > > From the documentation: > >      EXAMPLES: > >  

[sage-support] Re: Resultant of two polynomials

2011-01-26 Thread John Cremona
On Jan 26, 8:09 am, Santanu Sarkar wrote: > I have two polynomials F(x,y,z) and G(x,y,z) over integer. From F, G I want > to eliminate z by resultant method. How can I do this? >From the documentation: EXAMPLES: sage: P. = PolynomialRing(QQ,2) sage: a = x+y

[sage-support] Re: resultant

2010-02-01 Thread Simon King
Hi Michael, On Feb 1, 2:37 am, Michael Beeson wrote: > I let Mathematica run a similar problem for 36 hours with no reply; > but I don't understand why it's too difficult. Indeed, not easy. By the way, in your first example, you defined sage: R. = QQ[] sage: a = z^2 - z^-2 sage: f = z^2 *(p-a)

[sage-support] Re: resultant

2010-01-31 Thread Michael Beeson
Oh, gcd is the multivariate gcd, not the gcd as a polynomial in z. -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/

[sage-support] Re: resultant

2010-01-31 Thread Michael Beeson
But look at this: sage: F.gcd(G) z^2 + 1 Reply comes back instantly. This is really strange as it should have to perform more or less the same computation for the gcd as for the resultant, shouldn't it? And I would have expected the gcd to involve all those parameters, or at least some of the

[sage-support] Re: resultant

2010-01-31 Thread Michael Beeson
So taking your suggestion to use a quadratic number field, I get rid of syntax errors at last. But I guess the problem is too difficult as no answer comes back in a few minutes. I let Mathematica run a similar problem for 36 hours with no reply; but I don't understand why it's too difficult. Se

[sage-support] Re: resultant

2010-01-31 Thread Michael Beeson
"i" is sqrt(-1), which sage seems usually to realize without being told. Anyway there is no "i" in my first post on the resultant, and also I get the same error with "CC" in place of "QQ". On Jan 31, 3:38 pm, William Stein wrote: > 2010/1/31 Michael Beeson : > > > another failed attempt to comp