AM
To: sage-support@googlegroups.com
Subject: [sage-support] Re: matrix with many repeated entries
Thank you all for excellent help on the question.
I have another question along this line:
For p=20, q=20, r=1, s=2, t=2, I would like to define matrix
A=[a(i,j)] such that
for k in range(1,t+1), a(i
e-support
Subject: [sage-support] Re: matrix with many repeated entries
I dont quite understand the defining rule for your matrix, but in
general you can just put whichever rule you have as a function
def f(i,j):
if ((i<=5) and (j in [1,2,3, 7, ..., 20]))
return 1
if i in [6,7,1
In-Jae,
You can "stack" matrices, which would work here. If top and bottom
are matrices with identical number of columns, then top.stack
(bottom) will return the right thing. left.augment(right) will
build up a matrix "sideways." So for your question above:
sage: a=matrix(ZZ, 5, 20, [1]*(5
I dont quite understand the defining rule for your matrix, but in
general you can just put whichever rule you have as a function
def f(i,j):
if ((i<=5) and (j in [1,2,3, 7, ..., 20]))
return 1
if i in [6,7,13,..., 20]:
return 3
return -1
and then create your matrix us
t; Sent: Thursday, June 04, 2009 3:19 PM
> To: sage-support@googlegroups.com
> Subject: [sage-support] Re: matrix with many repeated entries
>
> Thank you for your help, Jason.
>
> Can I get some help on the following matrix too?
>
> a_{i,j} = 1 for 1 \leq i \leq 5 and j \
: [sage-support] Re: matrix with many repeated entries
Thank you for your help, Jason.
Can I get some help on the following matrix too?
a_{i,j} = 1 for 1 \leq i \leq 5 and j \in \{1,2,3, 7, ..., 20};
a_{i,j} =3 for i \in \{6, 7, 13, ..., 19\};
a_{ij}=-1 otherwise
>P.S. If you have any suggesti
ay, June 04, 2009 1:43 PM
To: sage-support@googlegroups.com
Subject: [sage-support] Re: matrix with many repeated entries
Kim, In-Jae wrote:
> Hello,
>
> I would like to create a matrix with many repeated entries, for example, a
> matrix with all entries equal to 1.
> How can I do this
Kim, In-Jae wrote:
> Hello,
>
> I would like to create a matrix with many repeated entries, for example, a
> matrix with all entries equal to 1.
> How can I do this efficiently when the size of the matrix is large?
>
Hi In-Jae,
In Python (i.e., Sage), you can duplicate a list by multiplying i
