philabuster wrote:
> This ordering makes it extremely difficult to do index association
> from the j-th term of the expansion back into constituent indices of
> each sum (i0,i1,i2,i3);
Well, Sage punts to Maxima (for the moment, anyway) to compute
the expansion. The terms are computed in the ord
ma...@mendelu.cz wrote:
> You can use commands orderless and ordergreat in Maxima to change the
> default behavior.
For the record, I recommend against that; it's not really the right
way to resolve this problem. I'll post another message with a
different resolution.
Robert Dodier
--~--~--
On 23 Dub, 20:38, William Stein wrote:
> New symbolics also tend to be easier to work with term-by-term:
>
> sage: v = expand((a0+a1)*(b0+b1))
> sage: v[0]
> a0*b0
> sage: v[1]
> a0*b1
> sage: v[2]
> a1*b0
> sage: v[3]
> a1*b1
-
Maxima 5.13.0 http:/
On 23 Dub, 20:38, William Stein wrote:
> On Thu, Apr 23, 2009 at 6:44 AM, philabuster wrote:
>
> > Hi,
>
> > I was wondering why Sage expands products of sums in an unexpected
> > order:
>
> > var('a0,a1,b0,b1,b2,c0,c1,c2,c3,d0,d1,d2,d3,d4')
>
> The ordering of these terms is determined by max
On Thu, Apr 23, 2009 at 6:44 AM, philabuster wrote:
>
> Hi,
>
> I was wondering why Sage expands products of sums in an unexpected
> order:
>
> var('a0,a1,b0,b1,b2,c0,c1,c2,c3,d0,d1,d2,d3,d4')
The ordering of these terms is determined by maxima -- Sage doesn't
control that at all, just leaving t
