On 15 May 2009, at 16:33, Mike Hansen wrote:
>
> In Sage 4.0 which will be released within the week, you'll be able to
> do the following:
>
> sage: var("a b c d e")
> (a, b, c, d, e)
> sage: e1 = a == b + c
> sage: e2 = d == e * a
> sage: e3 = e2.subs(e1); e3
> d == (b + c)*e
Well, that's what
Hello,
On Fri, May 15, 2009 at 5:06 AM, Paul Sargent wrote:
> Lets give ourselves two symbolic equations:
>
> sage: var("a b c d e")
> sage: e1 = a == b + c
> sage: e2 = d == e * a
>
> Now, lets say I want to know what c is in terms of b, d & e. By hand
> I'd substitute e1 in e2, and then solve
Not sure if this is what you are after, but the following would give you
the solution:
sage: solve([e1,e2],c,a)
[[c == (d - b*e)/e, a == d/e]]
You can give n equations to solve and solve for n variables. Solve will
insert one into another automatically.
An equation has a different syntax to a
