On 06/30/2010 05:06:19 AM, Burcin Erocal wrote:
On Fri, 25 Jun 2010 07:53:00 -0700
Mike Witt wrote:
> On 06/25/2010 06:07:02 AM, kcrisman wrote:
> > Dear Mike,
> >
> > Just to follow up:
> >
> > There is further discussion at
> > http://trac.sagemath.org/sage_trac/ticket/9329
> > if you are int
> As far as I understand from your previous comments, a way to extract the
> exponential functions from the expression is all you need. You don't
> really need to walk through the tree. Here is one way to do this:
>
> sage: t = exp(x+y)*(x-y)*(exp(y)+exp(z-y))
> sage: t
> (e^(-y + z) + e^y)*(x - y
On Fri, 25 Jun 2010 07:53:00 -0700
Mike Witt wrote:
> On 06/25/2010 06:07:02 AM, kcrisman wrote:
> > Dear Mike,
> >
> > Just to follow up:
> >
> > There is further discussion at
> > http://trac.sagemath.org/sage_trac/ticket/9329
> > if you are interested in saying exactly what sort of data st
On 06/26/2010 05:21:21 PM, kcrisman wrote:
> I believe that Ticket #9329 was generated in response to my original
> post, before I understood that there was a Latex issue involved.
> I believe that Ticket #9329 should be deleted (closed or whatever).
But part of your question was also to try to
> I believe that Ticket #9329 was generated in response to my original
> post, before I understood that there was a Latex issue involved.
> I believe that Ticket #9329 should be deleted (closed or whatever).
But part of your question was also to try to simplify more complicated
expressions, and i
On 06/26/2010 03:26:06 PM, Jason Grout wrote:
On 6/24/10 6:15 AM, kcrisman wrote:
Right. This crops up in the middle of a more complicated
expression. If I could figure out how to break the expression
up in the right way, then I guess I could search for parts
that are exponential functions, tak
On 6/24/10 6:15 AM, kcrisman wrote:
Right. This crops up in the middle of a more complicated
expression. If I could figure out how to break the expression
up in the right way, then I guess I could search for parts
that are exponential functions, take the log of those, and
then simplify the logs.
On 06/25/2010 06:07:02 AM, kcrisman wrote:
Dear Mike,
Just to follow up:
There is further discussion at
http://trac.sagemath.org/sage_trac/ticket/9329
if you are interested in saying exactly what sort of data structure
would enable you to perform the simplifications you would like to
without
Dear Mike,
Just to follow up:
There is further discussion at http://trac.sagemath.org/sage_trac/ticket/9329
if you are interested in saying exactly what sort of data structure
would enable you to perform the simplifications you would like to
without having to create a custom Maxima simplification
> I've noticed too about how maxima continues to ask things that
> (it would seem) you have already told it. I guess it would be
> in my best interests to learn more about maxima.
>
If you are serious about doing symbolic manipulation that you can
control from within Sage, yes. That said, variou
On 06/24/2010 06:15:52 AM, kcrisman wrote:
> > > sage: n=var('n')
> > > sage: f=e^(i*x*pi*n-i*2*pi*n)
> > > sage: f.simplify_full()
> > > e^(I*pi*n*x - 2*I*pi*n)
>
> > > # Is there a way I can get this to simplify?
>
> > This apparently isn't even that easy in Maxima.
>
> > Maxima 5.21.1http://
> > > sage: n=var('n')
> > > sage: f=e^(i*x*pi*n-i*2*pi*n)
> > > sage: f.simplify_full()
> > > e^(I*pi*n*x - 2*I*pi*n)
>
> > > # Is there a way I can get this to simplify?
>
> > This apparently isn't even that easy in Maxima.
>
> > Maxima 5.21.1http://maxima.sourceforge.net
> > using Lisp ECL 10.
On 06/22/2010 12:41:17 PM, kcrisman wrote:
> sage: n=var('n')
> sage: f=e^(i*x*pi*n-i*2*pi*n)
> sage: f.simplify_full()
> e^(I*pi*n*x - 2*I*pi*n)
>
> # Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima 5.21.1 http://maxima.sourceforge.net
using L
> sage: n=var('n')
> sage: f=e^(i*x*pi*n-i*2*pi*n)
> sage: f.simplify_full()
> e^(I*pi*n*x - 2*I*pi*n)
>
> # Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima 5.21.1 http://maxima.sourceforge.net
using Lisp ECL 10.4.1
Distributed under the GNU Publ
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