[sage-support] Re: Possibly wrong limit concerning log

2015-06-25 Thread kcrisman
> > Other examples of wrong limits with logarithm in exponent in Sage: >> lim27**(log(n,3/n**3),n=infinity) returns 0 (Wolfram Alpha >> >> >> and Maple return 1). >> lim27*

[sage-support] Re: Possibly wrong limit concerning log

2015-06-04 Thread kcrisman
> > > Other examples of wrong limits with logarithm in exponent in Sage: > lim27**(log(n,3/n**3),n=infinity) returns 0 (Wolfram Alpha > > > and Maple return 1). > lim27**(l

[sage-support] Re: Possibly wrong limit concerning log

2015-06-04 Thread pcworld
> > sympy, too, finds the limit despite not recognizing the identity: > … > expr = 27**(log(x,3)/x**3) > > expr, limit(expr, x, oo) > > Your expression has "1/x^3" in its exponent. The expression from the orginal post would be 27**(log(x,3))/x**3, which SymPy correctly simplifies and finds the

[sage-support] Re: Possibly wrong limit concerning log

2015-06-03 Thread ssinglet
On Monday, June 1, 2015 at 7:53:18 PM UTC-5, kcrisman wrote: > > I wonder if anyone else has any ideas here? > sympy, too, finds the limit despite not recognizing the identity: %python ​from sympy import * x = symbols('x') expr = 27**(log(x,3)/x**3) expr, limit(expr, x, oo) >>> (27**(lo

[sage-support] Re: Possibly wrong limit concerning log

2015-06-01 Thread kcrisman
> lim(27^log(n,3)/n^3, n=infinity) > Indeed, if you use http://en.wikipedia.org/wiki/List_of_logarithmic_identities#Canceling_exponentials you can easily see that the expression equals 1 in the first place! Plotting it yields the same. But unfortunately Maxima does not seem to have this id