Can you replace
L.level_sets()[-3:-2][0]
by
L.level_sets()[-3] ?
On Feb 25, 7:05 pm, Ryan Davis wrote:
> L.level_sets()[-3:-2][0][i].element.property() is the only way I've
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I was hoping to get at the individual elements listed by L.level_sets()
[-3:-2], but these seem to be stored in a 1 element list which
contains the actual list of elements in the specified level set, so
L.level_sets()[-3:-2][0][i].element.property() is the only way I've
been able to get at property
This may be the list you want (all one one line if it gets cut up
here):
indices = [f.element.ambient_ray_indices() for l in L.level_sets()
[-3:-2] for f in l]
And by "address individually" do you mean indices[0], indices[1], etc?
Rob
On Feb 24, 6:48 pm, Ryan Davis wrote:
> Greetings,
>
> I'm
