On Fri, 08 Nov 2013 at 01:41PM -0800, kcrisman wrote:
> Dan, I'm on a train with horrible internet - can you open a ticket, post to
> the Maxima list, etc.? Thanks!
This is now http://trac.sagemath.org/ticket/15386.
Dan
--
--- Dan Drake
- www.math.wisc.edu/~ddrake/
---
signature.
Another interesting data point - in Maxima itself:
(%i6) display2d:false;
(%o6) false
(%i7) limit(-(3*n^2 + 1)*(-1)^n/sqrt(n^5 + 8*n^3 + 8),n,inf);
(%o7) -38*und*log(-1)^2/25
But in Sage
sage: log(-1)
I*pi
which presumably leads to this.
Dan, I'm on a train with horrible internet - can you o
On Fri, 08 Nov 2013 at 01:03PM -0800, kcrisman wrote:
> Note the "und" - undefined. Maxima is probably noticing the (-1)^n piece...
I'm not sure it's the (-1)^n. I tried using cos(pi*n) instead and still
get "und":
sage: n = var('n')
sage: assume(n>0)
sage: series = -(3*n^2 + 1)*cos(pi*n)/sqrt(n
Looks like you are correct. When i took the absolute value of "series", it
gave me the correct answer. (Although absolute value doesn't work 100% of
the time.)
I'm currently doing (limit((series^2).simplify_full(), n=infinity))
It serves its purpose for now since I only want to know if the limit
On Friday, November 8, 2013 2:21:26 PM UTC-5, PavelY wrote:
>
> I am trying to compute a limit with sage, and I get incorrect answers.
>
> Here is an example which should produce the result of 0 but does not.
>
> reset()
> n = var('n')
>
> assume(n>0)
> series = -(3*n^2 + 1)*(-1)^n/sqrt(n^5 + 8
