On Jan 19, 1:43 pm, slabbe wrote:
> PROBLEM :
> In a list of vectors, I want to know if there is a pair of equal
> vectors.
>
> I have two solutions. The first to create an empty list L and append
> the vectors one per one. If a vector is already in L before adding it,
> then I found a pair of eq
You're right. This is what I meant:
sage: L = [vector([1,0,0]), vector([1,2,0]), vector([1,0,3]), vector([1,0,0])]
sage: LL = [tuple(v.list()) for v in L]
sage: Set(LL)
{(1, 0, 0), (1, 0, 3), (1, 2, 0)}
But that is probably what you said in the first place.
Here's another idea:
sage: L = [vect
> I don't know if this is the best idea or not but I definitely have
> run into this problem before and what I think I did was
> to store the list of vectors as a *Set* of *lists*.
Are you sure? Because as vectors, lists are unhashable :
...
TypeError: list objects are unhashable
--~--~-
I don't know if this is the best idea or not but I definitely have
run into this problem before and what I think I did was
to store the list of vectors as a *Set* of *lists*.
On Mon, Jan 19, 2009 at 4:43 PM, slabbe wrote:
>
> PROBLEM :
> In a list of vectors, I want to know if there is a pair of
