Thanks for the help.
On 21 January 2012 07:27, Maarten Derickx wrote:
> Well the way I first tried is as follows:
>
> age: F.=GF(2)[]
> sage: G.=F.quotient(x^6 + x^4 + x^2 + x + 1)
> sage: a.multiplicative_order()
> ---
> Not
Well the way I first tried is as follows:
age: F.=GF(2)[]
sage: G.=F.quotient(x^6 + x^4 + x^2 + x + 1)
sage: a.multiplicative_order()
---
NotImplementedError Traceback (most recent call last)
But it giv
Yes, exactly that we mean.
On 19 January 2012 20:13, John Cremona wrote:
> On 19 January 2012 15:39, Santanu Sarkar wrote:
>> Consider a polynomial f(x) over GF(2)[x]. How is it possible
>> to find the order of the cyclic group generated by f(x)?
>
> What do you mean by the group generated by th
On 19 January 2012 15:39, Santanu Sarkar wrote:
> Consider a polynomial f(x) over GF(2)[x]. How is it possible
> to find the order of the cyclic group generated by f(x)?
What do you mean by the group generated by the polynomial? Do you
mean the group generated by a root of f (when f is irreducib
Consider a polynomial f(x) over GF(2)[x]. How is it possible
to find the order of the cyclic group generated by f(x)?
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