See attachment.
Mathematica also has a MatrixExp command, and on 2 by 2 matrices the
answers are really nice. For example, if the matrix has complex
eigenvalues, the answers are written in terns of Sin and Cos rather than
exponentials of complex numbers.
On 01/24/13 11:20, Christophe BAL wr
I'm curious to see this output. Can you send it ?
2013/1/24 Stephen Montgomery-Smith
> On 01/24/13 08:57, Christophe BAL wrote:
>
>> Hello,
>> I would like, if it is possible, to calculate the formal power of one
>> matrix ?
>>
>> My attempt is after but it doesn't work... :-(
>>
>> Christophe
>
On 01/24/13 08:57, Christophe BAL wrote:
Hello,
I would like, if it is possible, to calculate the formal power of one
matrix ?
My attempt is after but it doesn't work... :-(
Christophe
==
var('n')
assume(n, 'integer')
E = matrix([
[0 , 1 , 0 , 0 , 0 ],
I don't think such a thing is possible in the way you are hoping for.
My suggestion would be to find the Jordan normal form (and save the conjugating
matrix by passing `transformation=True`). Your matrix is diagonalizable so you
can then take a formal exponential of that (though you may have to
Hello,
I would like, if it is possible, to calculate the formal power of one
matrix ?
My attempt is after but it doesn't work... :-(
Christophe
==
var('n')
assume(n, 'integer')
E = matrix([
[0 , 1 , 0 , 0 , 0 ],
[1/4 , 0 , 3/4 , 0 , 0 ],
[0 , 1/
