Why does the plot
plot(k%1,k,0,5)
is not produced but the following works:
k=var('k')
plot( k/1, k,0,5).show()
print 1.9%1
What can be used instead ?
Pedro
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There is matplotlib
http://matplotlib.sourceforge.net/examples/pylab_examples/boxplot_demo.html?highlight=boxplot
http://matplotlib.sourceforge.net/plot_directive/mpl_examples/pylab_examples/boxplot_demo.py
I also didn't get it with R in sage (or python).
Pedro Cruz
On Mar 14, 7:22 am, mo wr
I've tried with
print pool.map(f, range(10))
instead of
pool.map(f, range(10))
calling python file.py
In the notebook, the output must be caughted and printed for user, I
think.
Pedro
On Mar 7, 5:23 am, Gokhan Sever wrote:
> Hello,
>
> I am executing this example in Sage Notebook
)
print TrivialSageJSON().encode({"a": 123})
If any thing better (more general) appears please let me know.
Thanks,
Pedro
On Feb 20, 12:17 am, Mike Hansen wrote:
> On Fri, Feb 19, 2010 at 3:52 PM, jpc wrote:
> > Should one do the "type cast" below for every int or floa
Python json library is of simple use but there's this problem:
sage: import json
sage: json.dumps( {"a": 1.8} )
...produce an error because:
sage: x = 1.8
sage: type(x)
Should one do the "type cast" below for every int or float when using
sage ?
sage: type(float(x))
sage: json.dumps( {"a": flo
Hi,
I've search on
http://rpy.sourceforge.net/
and use R with commands inside a Sage script as following:
from sage.all import *
def iunif(a,b):
return Integer(fround(r.runif(1,RDF(a),RDF(b)),0))
def runif(a,b,prec):
return RDF(fround(r.runif(1,RDF(a),RDF(b)),prec))
def rbernoulli():
In a sage notebook one can write:
%latex
$\int_a^b x dx$
to *see the integral*.
Or is other problem?
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hat continuity
of $f$ is necessary.
jpc
On Mar 15, 3:54 am, yacob wrote:
> f(x)=1/x
> r1=find_root(f,-1,1);r1
> -1.8189894035440371e-12
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