I have not yet benchmarked it but am working on it, however it is
definitely slower in comparison to Ripser / gudhi and co. (although if I
understand correctly Ripser only computes homology for Vietoris-Rips
complexes?), since it is a very direct python implementation of
Zomorodian's algo with
Hello all,
I know I am a bit late to the party, but I have written a Sage module for
computing persistent homology, and I just submitted a ticket !
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Hello,
I don't know if this is the right place to submit bugs.
I have consistently reproduced the following bug:
using set_block when matrix space is on a given NumberField or an extension
field (at least
when there are multiple generators) works as expected the first time (in a
sage sessio
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Le 10/04/2015 09:42, Jori Mantysalo a écrit :
> On Wed, 8 Apr 2015, Guillaume CONNAN wrote:
>
>>>> p1 = lambda z: ((3*z^3 | 2*z^2) ^^ 5*z) + 2
>>>
>>> What is the supposed result of
>>>
>>> 3
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Le 08/04/2015 09:26, Jori Mantysalo a écrit :
> On Sat, 4 Apr 2015, Guillaume CONNAN wrote:
>
>> p1 = lambda z: ((3*z^3 | 2*z^2) ^^ 5*z) + 2
>
> What is the supposed result of
>
> 3*z^3 | 2*z^2
p1(2) is ((24 | 8) ^^ 10) +
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Le 03/04/2015 19:19, Jori Mantysalo a écrit :
> On Fri, 3 Apr 2015, Guillaume CONNAN wrote:
>
>> it's to do something like ( P1 * P2 | a ) & P3 + 2
>
> Can you give a concrete example of "P1 * P2 | a"?
somethi
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Le 03/04/2015 11:23, Jori Mantysalo a écrit :
> On Thu, 2 Apr 2015, Guillaume CONNAN wrote:
>
>> is there a library to do some symbolic calculations over integer
>> but with bitwise operations ? I need to work on symbolic
>
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Hello,
is there a library to do some symbolic calculations over integer but
with bitwise operations ?
I need to work on symbolic polynomials mixing arithmetic + and * and
bitwise >> << & | ^ .
Thanks,
- --
Guillaume Conna
OK, but what about the assume(k>0) which is not assumed ?
sage: x=var('x')
sage: f=function('f',x)
sage: k=var('k')
sage: assume(k>0)
sage: desolve(diff(f(x),x,2)/f(x)==k,[f,x])
TypeError: Computation failed since Maxima requested additional
constraints (try the command 'assume(k>0)' before i
Hello,
I want to solve f''/f=k with k in R
sage: x=var('x')
sage: f=function('f',x)
sage: k=var('k')
sage: desolve(diff(f(x),x,2)/f(x)==k^2+1,[f,x])
k1*e^(I*sqrt(-k^2 - 1)*x) + k2*e^(-I*sqrt(-k^2 - 1)*x)
I put k^2+1 since sage would'nt solve even with assume(k>0)
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mmand 'assume(k>0)' before integral or limit
evaluation, for example):
Is k positive, negative, or zero?
sage:
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and weirder...
sage: a*sinh(log(a)).substitute_function(sinh,sh).simplify_full()
1/2*a*log(a) - 1/2
sage: t*sinh(log(t)).substitute_function(sinh,sh).simplify_full()
1/2*t^2 - 1/2
this 1/2*a*log(a) - 1/2 is a bit unexpected...
well, I'm discovering sage but these results look strange.
che
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