On Dec 7, 2008, at 1:00 AM, Robert Bradshaw wrote:
>
> In Python you can pass functions around just like anything else. For
> example
>
> sage: def foo(x): return x*x
> :
> sage: def call_it(f, n): return f(n)
> :
> sage: call_it(foo, 5)
> 25
>
That's handy. I wasn't expecting for it to
On Dec 6, 2008, at 9:48 PM, Tim Lahey wrote:
>
> Hi,
>
> This is more of a python question than a Sage one,
> but I kind of need to figure this out for the
> integral test suite. I'd like to pass the name of
> a function into another function in order to
> carry out the comparison. This may chang
Hi,
This is more of a python question than a Sage one,
but I kind of need to figure this out for the
integral test suite. I'd like to pass the name of
a function into another function in order to
carry out the comparison. This may change depending
on the integral so I'd like to store the name in
On Sat, Dec 6, 2008 at 12:25 PM, wayne w <[EMAIL PROTECTED]> wrote:
>
> ~/bash$sage
> --
> | Sage Version 3.2.1, Release Date: 2008-12-01 |
> | Type notebook() for the GUI, and license() for information.
BTW, one gan get the generator with the gen() method.
sage: R = GF(101)['y']
sage: R.gen()
y
An even easier shorthand is
sage: R. = GF(101)['y']
or even simply
sage: R. = GF(101)[]
where the y appears on the left hand side, so an assignment is made.
- Robert
On Dec 6, 2008, at 12:09 PM, j
~/bash$sage
--
| Sage Version 3.2.1, Release Date: 2008-12-01 |
| Type notebook() for the GUI, and license() for information.|
--
s
Robert,
Okay, I see the difference: a polynomial generator "over" the ring
means something that will generate a ring over the given ring, not a
polynomial generator "of" the ring.
thanks
john perry
On Dec 6, 12:31 pm, Robert Bradshaw <[EMAIL PROTECTED]>
wrote:
> I think you are misinterpreting
On Sat, Dec 6, 2008 at 6:27 AM, Rafael <[EMAIL PROTECTED]> wrote:
> Hello William,
>
> That seems to work great, except for the problem of computing the
> hermitian conjugate of the unitary matrix u,
> since
>
> sage: K. = QQ[sqrt(-1), sqrt(2)]
> sage: j.conjugate()
> 0
>
> Can one define a conjug
I think you are misinterpreting polygen. Polygen takes as input a
ring, and creates a new polynomial ring over that rings, and returns
the generator of that new ring (not the generator of the original
ring). Also, since you didn't provide a name to the polygen function,
it defaults to "x."
Sorry, I didn't expect that. Here are two examples:
sage: R = GF(101)['y']
sage: y = polygen(R)
sage: type(y)
sage: y^3/y^2
x^3/x^2
sage: simplify(y^3/y^2)
x^3/x^2
sage: R.inject_variables()
Defining y
sage: type(y)
sage: y^3/y^2
y
This is what t
On Dec 6, 8:17 am, "William Stein" <[EMAIL PROTECTED]> wrote:
> On Fri, Dec 5, 2008 at 10:12 PM, Jason Grout
>
>
>
> <[EMAIL PROTECTED]> wrote:
>
> > Jan Groenewald wrote:
> >> Hi
>
> >> On Thu, Dec 04, 2008 at 11:22:11AM -0600, Jason Grout wrote:
> http://sagenb.org:8000/home/pub/94/and inclu
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