michel paul wrote:
You could use *n for your parameter. It allows you to enter an arbitrary number
of arguments:
def a(*n): return [1/k^2 for k in n]
a(2,4,6) ---> [1/4,1/16,1/36]
a(5) ---> [1/25]
Not exactly what you were wanting, but pretty close.
But - why not just go ahead and define
You could use *n for your parameter. It allows you to enter an arbitrary
number of arguments:
def a(*n): return [1/k^2 for k in n]
a(2,4,6) ---> [1/4,1/16,1/36]
a(5) ---> [1/25]
Not exactly what you were wanting, but pretty close.
But - why *not* just go ahead and define a(n) for the nth term
Jamie Mulholland wrote:
Could use the map command:
sage: a(n)=n^2
sage: map(a,[1,2,3])
[1,4,9]
Cheers
Jamie
On Wed, Nov 2, 2011 at 9:52 AM, A. Jorge Garcia wrote:
> My discrete math class was playing with sequences today.
>
> Example 1)
> a(n)=1/n**2
> for I in range(1,10):
>show(a(I))
>
On 11/2/11 12:16 PM, Jamie Mulholland wrote:
Could use the map command:
sage: a(n)=n^2
sage: map(a,[1,2,3])
[1,4,9]
Or list comprehensions:
[n^2 for n in [1,2,3]]
or
[a(n) for n in [1,2,3]]
-Jason
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Could use the map command:
sage: a(n)=n^2
sage: map(a,[1,2,3])
[1,4,9]
Cheers
Jamie
On Wed, Nov 2, 2011 at 9:52 AM, A. Jorge Garcia wrote:
> My discrete math class was playing with sequences today.
>
> Example 1)
> a(n)=1/n**2
> for I in range(1,10):
> show(a(I))
>
> Example 2)
> [a(n) for I
