On Jun 30, 2:26 am, Rob Beezer wrote:
> sage: V = GF(3)^3
> sage: W = QQ^2
> sage: H = Hom(V, W)
> sage: m = matrix(3, 2, range(6))
> sage: f = H(m)
This makes no sense at all; the function is not a homomorphism:
sage: v = [V.random_element() for i in range(2)]
sage: l = [GF(3).random_element
On Jun 29, 7:39 pm, Roman Sinayev wrote:
> Ok, I changed the PATH (removed /local/ stuff) and it didn't help. I
> think i have the local folder as a part of the default PATH on my
> ubuntu notebook as well.
>
> Which log would I look at in the build directory?
python-2.6.4.p11/src/config.log
l
Bonjour,
Pour information:
Conférence PyCONFR 2011
17 et 18 Septembre 2011
Rennes, France
Rendez-vous annuel des utilisateurs de Python organisé par
l'Association Francophone Python
http://www.pycon.fr/conference/edition2011
Quelqu'un ser
On Jun 29, 3:49 pm, Florent Hivert
wrote:
> Hi David,
>
> > I thought it had been agreed no package would be standard unless it
> > is first optional.
>
> There were indeed such an agreement. However, I'd rather following the idea of
> the rule rather than the letter.
[...]
> I don't see the
The log is here:
http://dl.dropbox.com/u/6726175/config.log
On Jun 30, 4:26 am, Dima Pasechnik wrote:
> On Jun 29, 7:39 pm, Roman Sinayev wrote:
>
> > Ok, I changed the PATH (removed /local/ stuff) and it didn't help. I
> > think i have the local folder as a part of the default PATH on my
> > u
> On Jun 29, 3:49 pm, Florent Hivert
>
> wrote:
> > Hi David,
> >
> > > I thought it had been agreed no package would be standard unless it
> > > is first optional.
> >
> > There were indeed such an agreement. However, I'd rather following the
> > idea of the rule rather than the letter.
Le 30 juin 2011 09:48, Nicolas M. Thiery a écrit :
> Bonjour,
>
> Pour information:
>
> Conférence PyCONFR 2011
> 17 et 18 Septembre 2011
> Rennes, France
>
> Rendez-vous annuel des utilisateurs de Python organisé par
> l'Association Francophone Python
>
>
On Jun 30, 1:05 am, Francis Clarke wrote:
Thanks, Francis. Very astute.
> This makes no sense at all; the function is not a homomorphism:
Right.
So K^2 is a 4-dimensional vector space over the rationals. But you've
represented f with a 2 x 2 matrix.
Despite f above acting as a homomor
