2009/9/3 John H Palmieri :
>
> On Sep 3, 12:36 am, William Stein wrote:
>>
>> Sage has the Gaussian integers, and I'm sure the basic arithmetic and
>> functionality is as good or better than Mathematica already.
>>
>> sage: R. = ZZ[sqrt(-1)]; R
>> Order in Number Field in I with defining polynomi
On Thu, Sep 3, 2009 at 9:15 AM, John H Palmieri wrote:
>
> On Sep 3, 12:36 am, William Stein wrote:
> >
> > Sage has the Gaussian integers, and I'm sure the basic arithmetic and
> > functionality is as good or better than Mathematica already.
> >
> > sage: R. = ZZ[sqrt(-1)]; R
> > Order in Number
On Sep 3, 12:36 am, William Stein wrote:
>
> Sage has the Gaussian integers, and I'm sure the basic arithmetic and
> functionality is as good or better than Mathematica already.
>
> sage: R. = ZZ[sqrt(-1)]; R
> Order in Number Field in I with defining polynomial x^2 + 1
Okay, this looks like a b
> is this not just a curiosity? Maybe a useful one for teaching,
> though, and implementing this would certainly be possible.
Very useful. I had to resort to some annoying crutches (i.e., using
the theorem in the code instead of "discovering" the theorem via the
demonstration of the code) to
2009/9/3 javier :
>
>
> On Sep 3, 9:36 am, William Stein wrote:
>> Sage has the Gaussian integers, and I'm sure the basic arithmetic and
>> functionality is as good or better than Mathematica already.
>
> Sure, what I meant (sorry if I wasn't very clear) is to make an
> straightforward way to acc
On Sep 3, 9:36 am, William Stein wrote:
> Sage has the Gaussian integers, and I'm sure the basic arithmetic and
> functionality is as good or better than Mathematica already.
Sure, what I meant (sorry if I wasn't very clear) is to make an
straightforward way to access it, kind of
R = GaussianI
2009/9/3 javier
>
> Hi William,
>
> On Sep 3, 8:18 am, William Stein wrote:
> > I am not sure what something like "integers with I adjoined" is?
>
>
> I guess that means the complex numbers of the fomr a + bI with a, b
> integers, or Z[I] (the Gaussian Integers). Mathematica prides itself
> to
Hi William,
On Sep 3, 8:18 am, William Stein wrote:
> I am not sure what something like "integers with I adjoined" is?
I guess that means the complex numbers of the fomr a + bI with a, b
integers, or Z[I] (the Gaussian Integers). Mathematica prides itself
to be able to apply primality tests,
2009/9/2 Dirk
>
> I'm the originator. In fairness to Jan, I must say that I only showed
> him the code and output with no other comment than that I hoped that
> the students would not ask me to explain it.
>
> I've in the meantime found a way of illustrating the point I meant to
> make more clea
I'm the originator. In fairness to Jan, I must say that I only showed
him the code and output with no other comment than that I hoped that
the students would not ask me to explain it.
I've in the meantime found a way of illustrating the point I meant to
make more clearly.
sage: z=1.+sqrt(-1)
sa
Hi William
On Wed, Sep 02, 2009 at 11:18:40PM -0700, William Stein wrote:
>If you take any integer (or rational) alpha such that alpha is not a
>perfect square, and try to compute sqrt(alpha), Sage promotes alpha to the
>symbolic ring (SR) and takes the square root there. Thus the fi
2009/9/2 Jan Groenewald
>
> Hi William
>
> On Wed, Sep 02, 2009 at 10:31:01PM -0700, William Stein wrote:
> > Is this the intended behaviour?
> >
> > sage: z=1.+sqrt(-1); print z; z.base_ring()
> > 1.00 + 1.00*I
> > Symbolic Ring
> > sage: z=1.+sqr
Hi William
On Wed, Sep 02, 2009 at 10:31:01PM -0700, William Stein wrote:
> Is this the intended behaviour?
>
> sage: z=1.+sqrt(-1); print z; z.base_ring()
> 1.00 + 1.00*I
> Symbolic Ring
> sage: z=1.+sqrt(-1.); print z; z.base_ring()
> 1.000
On Wed, Sep 2, 2009 at 9:56 PM, Jan Groenewald wrote:
>
> Hi
>
> Sage-support did not solicit an answer.
> Both of these seem wrong:
>
> Is this the intended behaviour?
>
> sage: z=1.+sqrt(-1); print z; z.base_ring()
> 1.00 + 1.00*I
> Symbolic Ring
> sage: z=1.+sqrt(-1.);
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